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bonufazy [111]
3 years ago
13

HELP PLEASE!!!!!!!! I WILL MARK BRAINLIEST!!!!!!!​

Chemistry
1 answer:
Arlecino [84]3 years ago
8 0

Answer: option  d

MARK BRAINLIEST!!!!!!

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A bag of soil will weigh in kilograms
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3 years ago
Read 2 more answers
Differentiate between Acidic radical and basic radical ​
Paladinen [302]

Explanation:

<em>Acidic</em><em> </em><em>radical</em><em> </em>

<em>Acid radical is the ion formed after the removal of Hydrogen ion (H+) from an acid. Example: When H2SO4 loses H+ ion, it forms HSO4− which is an acid radical.</em><em> </em>

<em>Basic</em><em> </em><em>radical</em><em> </em>

<em> The ion formed after the removal of hydroxide ion (OH−) from a base is known as basic radical.</em>

3 0
3 years ago
28) Consider a 21.0 mL sample of pure lemon juice with a citric acid (H3C6H5O7) concentration of 0.30M. a. How many moles of cir
Damm [24]
<h3>#a. Answer:</h3>

0.0063 mole

<h3>Solution and explanation:</h3>

We are given 21.0 mL citric acid with a concentration of 0.30 M

Part a requires we calculate the number of moles of citric acid.

We need to know how to calculate the concentration of a solution;

Concentration or molarity = Number of moles ÷ Volume of the solution

Thus;

Number of moles = Concentration × Volume

Hence;

Moles = 0.30 M × 0.021 L

         = 0.0063 mole

<h3>#b. Answer</h3>

1.21 g citric acid

<h3>Solution</h3>

Part B

We are required to calculate the mass of citric acid in the sample

Number of moles of a compound is calculated by dividing its mass by its molar mass.

Molar mass of Citric acid = 192.124 g/mol

Moles of citric acid = 0.0063 mole

But; Mass = Number of moles × Molar mass

Mass of citric acid = 0.0063 mol × 192.124 g/mol

                             = 1.21 g citric acid

<h3>#c. Answer</h3>

4.167 mL

<h3>Solution:</h3>

Part C

We are required to determine the initial volume before dilution;

We have;

Initial concentration (M1) = 0.30 M

Final volume (V2) = 250 mL or 0.25 L

Final concentration (M2) = 0.0050 M

Using the dilution formula we can get the initial volume;

Therefore, since; M1V1 =M2V2

V1 = M2V2÷M1

   = (0.0050 × 0.25)÷ 0.30

   = 0.004167 L or

   = 4.167 mL

Therefore, the initial volume of the solution is 4.167 mL

8 0
3 years ago
Ch3cooh (acetic acid) can form hydrogen bonds between its molecules. based on the lewis structure shown below, how many hydrogen
never [62]
Answer:
           Number of Hydrogen Bond Acceptor atoms  =  2

           Number of Hydrogen Bond Donor atoms  =  1

Explanation:
                   Hydrogen bond interactions are formed between those molecules which contains partial positive hydrogen atoms bonded covalently to most electronegative atoms like Oxygen, Nitrogen and Fluorine. 
                   When hydrogen is attached to Oxygen, Nitrogen or Fluorine its electron density decreases and gets partial positive charge, this partial positive charged hydrogen atom then makes hydrogen bonding with the most electronegative element (partial negative) of neighbor molecule.
                    In Acetic acid there are two oxygen atoms hence there are two most electronegative elements therefore, two Hydrogen Bond Acceptor atom and each oxygen atom can accept two hydrogen bonds.
                    Also, it contains only one Hydrogen atom attached to oxygen atom so it has one Hydrogen Bond Donor atom.

4 0
3 years ago
19. Which of the following chemical equations represents
Lesechka [4]

Answer:

  • C₃H₈ (g) + 5O₂(g) → 3CO₂ (g) + 4H₂O (l)

(option D. with the proviso that the subscripts of propane's chemical formula must be corrected)

Explanation:

<em>Propane</em> is the saturated hydrocarbon, alkane, with chemical formula C₃H₈ or CH₃CH₂CH₃.

The complete combustion of the hydrocarbons yield carbon dioxide (CO₂) and water (H₂O).

The chemical equation that represents this combustion is:

  • C₃H₈ (g) + O₂(g) → CO₂ (g) + H₂O (l) (skeleton equation: unbalanced)

Once you balance it, you get:

  • C₃H₈ (g) + 5O₂(g) → 3CO₂ (g) + 4H₂O (l)

        Left side           Right side

C         3                          3

H         8                          4×2 = 8

O        5×2 = 10               3×2 + 4 = 10

That equation corresponds to the option D. of the list, with the proviso that the subscripts of propane's chemical formula must be corrected

6 0
3 years ago
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