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2 years ago

Why is studying light and electrons important for chemistry and understanding the universe?

Chemistry

1 answer:

Brut [27]2 years ago

7 0

Explanation :

The study of light and electrons are important for chemistry & universe.

As we know, everything is made up of particles even light & universe also. The particles are made of atoms and that atoms are made up of electrons, protons & neutrons.

An electron is one of the most important type of subatomic particles. Electrons combine with the proton to form atom. These electrons, protons & neutrons play a vital role in chemistry and universe.

The importance of an electron is that when two atoms react with each other or approach each other, their outermost shells come into contact first and these outermost shells electrons are involved in the chemical reaction.

Also important for chemical reactions, creating bonds, for electricity and the understanding of electrons has allowed for the better understanding of some forces which are in our universe such as electromagnetic force.

We know that the light is act as particle nature and it is a part of universe. As we know that chemists are only responsible for the chemical's study. Chemists cannot study the whole universe that is why they study light and the light is important because nothing would be able to survive.

The studying of light is important for the photoelectric effect, absorption, bio-molecules synthesis, vitamin D synthesis, vision, colors, drying & evaporation, sterilization, solar energy, spectroscopy, signal system and also for electron excitation.

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What is keq for the reaction 2so2(g) + o2(g) 2so3(g)? apex?

Dennis_Churaev [7]

The keg for the reaction
2 SO2(g) + O2(g) → 2 SO3(g) is

Keg = [SO3]^2/ {(SO2)^2 ( O2)}

Keg (equilibrium constant) is the ratio of of equilibrium concentration of the product raised to the power of their stoichiometric coefficient to the equilibrium concentration of the reactant raised to the power of their stoichiometric coefficient.

7 0

3 years ago

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Intermolecular forces do not have any effect on determining the physical properties of

djyliett [7]

Answer:

False

Explanation:

The physical properties of melting point, boiling point, vapor pressure, evaporation, viscosity, surface tension, and solubility are related to the strength of attractive forces between molecules. These attractive forces are called Intermolecular Forces.

6 0

3 years ago

A sample of an unknown substance has a mass of 0.158 kg. If 2,510.0 J of heat is required to heat the substance from 32.0°C to 6

Alexxandr [17]

Specific heat capacity is the required amount of heat per unit of mass in order to raise teh temperature by one degree Celsius. It can be calculated from this equation: H = mCΔT where the H is heat required, m is mass of the substance, ΔT is the change in temperature, and C is the specific heat capacity.

H = mCΔT
2501.0 = 0.158 (C) (61.0 - 32.0)

C = 545.8 J/kg·°C

5 0

3 years ago

Part a use these data to calculate the heat of hydrogenation of buta-1,3-diene to butane. c4h6(g)+2h2(g)→c4h10(g)

Reptile [31]

Answer: The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]$

For the given chemical reaction:

$C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]$

We are given:

$\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J$

Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

4 0

2 years ago

vlada-n [284]

Answer:

El cocodrilo se arrastró durante 20.833 segundos.

Explanation:

El enunciado presenta omisiones y errores conceptuales. La forma correcta es la siguiente: "Un cocodrilo se arrastró 25 metros hacia la derecha con una rapidez promedio de 1.2 metros por segundo. ¿Cuántos segundos se arrastró el cocodrilo?"

Consideremos que el cocodrilo tiene un movimiento rectilíneo uniforme, el tiempo requerido para el recorrido se calcula con la siguiente ecuación cinemática:

$t = \frac{x}{v}$ (1)