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Stolb23 [73]
3 years ago
15

The absolute temperature of a gas increased four times while maintaining a constant volume. What happens to the pressure of the

gas?
Chemistry
1 answer:
andre [41]3 years ago
8 0

Following the ideal gas law PV = nRT, and changing it in terms of pressure we get P = nRT/V. When the absolute temperature of a gas is increased four times while maintaining constant volume, the pressure of the gas also increases four times. The pressure increases because temperature is directly proportional with pressure.

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Answer: velocity

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A popular car has a gas tank that holds a maximum of 14.5 gallons of fuel. What is
gulaghasi [49]

Taking into account the change of units, the size of the tank is 54.88 liters.

In first place, the rule of three is a tool used to quickly solve problems involving a proportional relationship between two variables.

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other), the direct rule of three should be applied.

The rule of three is applied as follows, with A, B and C being known values ​​and D being an unknown value: if A maintains a certain relationship with B, and it is known that C and D have the same relationship, it is possible to calculate the unknown value D using the following expression:

D=\frac{CxB}{A}

In this case, the rule of three can be applied as follows: if 1 gallon is equal to 3.785 liters, 14.5 gallons are equal to how many liters?

D=\frac{14.5 gallonsx3.785 liters}{1 gallon}

Solving:

D= 54.88 liters

In summary, the size of the tank is 54.88 liters.

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<h3>How to determine the volume occupied by the gas in a balloon </h3>

Let suppose that <em>flammable</em> hydrogen behaves ideally. GIven the molar mass (M), in kilograms per kilomole, and mass of the gas (m), in kilograms. The volume occupied by the gas (V), in cubic centimeters, is found by the equation of state for <em>ideal</em> gases:

V = \frac{m\cdot R_{u}\cdot T}{P\cdot M}   (1)

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  • T - Temperature, in Kelvin
  • P - Pressure, in kilopascals

If we know that m = 0.239\,kg, R_{u} = 8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K}, T = 273.15\,K, P = 101.325\,kPa and M = 2.02\,\frac{kg}{kmol}, then the volume of the balloon is:

V = \frac{(0.239\,kg)\cdot \left(8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K} \right)\cdot (273.15\,K)}{\left(101.325\,kPa\right)\cdot \left(2.02\,\frac{kg}{kmol} \right)}

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The volume of the balloon is approximately 2652 liters. \blacksquare

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