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2 years ago

Solve the inequality: -15 + 5x > 25

Mathematics

2 answers:

goldenfox [79]2 years ago

7 0

Answer:

x > 8

Step-by-step explanation:

-15 + 5x > 25

Add 15 on both sides

5x > 40

x > 8

Sever21 [200]2 years ago

5 0

Answer:

here

Step-by-step explanation:

inequality form ---- x>8

interval form ----- (8,infinite)

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3 years ago

This probability distribution shows thetypical grade distribution for a Geometrycourse with 35 students.GradeАBсDFFrequency 5101

Serggg [28]

Probability is expressed as

number of favourable outcomes/total number of possible outcomes

Looking at the given scenario, the number os students that earned a grade of A is 5. Since we are concerned with these students, then, the number of favourable outcomes is 5.

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Thus, the probability that a student earns a grade of A is

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9 months ago

The basic sticker price on Mr. Feldman's new car was $3200, The options he desired cost an additional $1800. What percent of the

Keith_Richards [23]

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6 0

3 years ago

A catapult launches a boulder with an upward velocity of 120 ft/s. The height of the boulder, h,

Vlad1618 [11]

Answer:

Reaches a maximum height of 235.00 feet in 3.75 seconds.

Step-by-step explanation:

The height of the boulder, h, in feet after t seconds is given by the function is given by :

$h=-16t^2+120t+10$ .....(1)

For maximum height, put $\dfrac{dh}{dt}=0$

i.e.

$\dfrac{d(-16t^2+120t+10)}{dt}=0\\\\-32t+120=0\\\\32t=120\\\\t=3.75\ s$

Put t = 3.75 in equation (1). So,

$h=-16(3.75)^2+120(3.75)+10\\\\h=235\ \text{feet}$

So, the boulder's maximum height is 235 feets and it takes 3.75 s to reach to its maximum height.

3 0

2 years ago

During a business trip, an individual stopped at two rest stops. In the parking lot of the first rest stop, they counted 20 cars

olganol [36]

Answer

given,

on first stop

number of car = 20 and number of trucks = 18

on second stop

number of car = 18 and number of trucks = 10

we need to calculate which rest stop has higher ratio of car to truck.

Rest Stop 1

ratio= r₁ = $\dfrac{cars}{trucks}$

r₁ = $\dfrac{20}{18}$

r₁ = $\dfrac{10}{9}$

Rest Stop 2

ratio= r₂ = $\dfrac{cars}{trucks}$

r₂ = $\dfrac{18}{10}$

r₂= $\dfrac{9}{5}$

hence, r₂ > r₁

rest stop 2 has more car to truck ratio than rest stop 1

3 0

2 years ago