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3 years ago

Question 1 (1 point)

Chemistry

1 answer:

andrezito [222]3 years ago

5 0

Answer:

True 
B. 24 hours 
Light and Dark 
A. To spin on an Axis 
True 
Nearest P0INTS 
B. 365 days 
True 
A. January 
B. July 
Summer 
B. The tilt of the Earth on its axis
True 
¿-¿
¿-¿
B. June
A. September 
B. December and March

Explanation:

Sorry yan lang alm but I hope it helps

<h2>#CARRYONLEARNING </h2><h2>#STUDYWELL </h2>

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Jaime is learning how elements are placed in the periodic table. He must find an element similar

Inessa05 [86]

Answer:

magnesium (Mg)

Explanation:

Both are in group 2 and because of that share the same chemical properties.

4 0

3 years ago

Common additives to drinking water include elemental chlorine, chloride ions, and phosphate ions. Recently, reports of elevated

NeX [460]

Answer:

Check the explanation

Explanation:

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8 0

3 years ago

Convert the MCL of antimony from milligrams per liter to parts per billion (ppb).

Aleks [24]

This is an incomplete question, here is a complete question.

According to the EPA, the maximum contaminant level (MCL) of antimony in drinking water is 0.0060 mg/L.

Convert the MCL of antimony from milligrams per liter to parts per billion (ppb).

Answer : The maximum contaminant level (MCL) of antimony in drinking water in parts per billion is, 6 ppb

Explanation :

ppb : It is defined as the mass of solute present in per 1000 million $(10^{-9}g)$ of total mass.

1 ppb = $\frac{10^{-9}g\text{ of solute}}{1g\text{ of solution}}$

As we know that:

1 milligrams per liter = 1000 parts per billion

or,

1 mg/L = 1000 ppb

As, 1 mg/L = 1000 ppb

So, 0.0060 mg/L = $\frac{0.0060mg/L}{1mg/L}\times 1000\text{ ppb}$

= 6 ppb

Thus, the maximum contaminant level (MCL) of antimony in drinking water in parts per billion is, 6 ppb

6 0

3 years ago

How do you find the percent composition of CuBr2

Levart [38]

Answer:

Explanation: the molar mass of the whole compound is 223.35u

now make ratios for each of the elements and multiply by 100%

copper= 63.55/223.35 x 100 % comp of copper is 28.45%

bromine= (79.9x2)/223.35 x 100 %comp of bromine is 71.54%

multiply bromines molar mass by 2 when calculating

7 0

3 years ago

A compound is formed when 12.2 g mg combines completely with 5.16 g n. what is the percent composition of this compound? please

Brums [2.3K]

To get the percent composition of an element in a compound, simply divide the mass of the element by the total mass of the compound. And since we're going to need to calculate the percentage a couple of times, let's first start by calculating the total mass of the compound:
M = 12.2 g + 5.16g = 17.36 g
Now the percentage of magnesium:
12.2 g / 17.36 g = 0.702764977 = 70.3%
And the percentage of nitrogen:
5.16 g / 17.36 g = 0.297235023 = 29.7%
Magnesium = 70.3%
Nitrogen = 29.7%

6 0

4 years ago