Mass of methane takne = 1.5g
moles of methane used = masss / molar mass = 1.5 / 16 = 0.094 moles
mass of water = 1000 g
Initial temperature of water = 25 C
final temperature = 37 C
specific heat of water = 4.184 J /g C
1) Heat absorbed by water = q =m• C• ΔT = 1000 X 4.184 x (37-25) = 50208 Joules
2) Heat absorbed by calorimeter = Heat capacity X ΔT = 695 X (37-25) = 8340 J
3) Total heat of combustion = heat absorbed by water + calorimeter = 50208 + 8340 = 58548 Joules
This heat is released by 0.094 moles of methane
So heat released by one mole of methane =
- 622851.06 Joules = 622.85 kJ / mole
4) standard enthalpy of combustion = -882 kJ / mole
Error = (882-622.85) X 100 / 882 = 24.84 %
Based on the given molecular formula, the molar mass of ethylene glycol is 62 g/mol. We solve for the number of moles of the solute,
n = (7.1 kg)(1000 g/ 1 kg) / 62g/mol = 114.52 mol
Then, we divide this value by the given mass of the water in kg
m = (114.52 mol) / 1.2 kg = 95.43 m
Thus, the molality of the substance is approximately equal to 95.43 m.
The energy which is required to split a nucleus into its discrete neutrons and protons is said to be nuclear binding energy.
Using the formula for nuclear binding energy:
E = Δmc²
where,
E = nuclear binding energy
Δm = mass defect
c = speed of light
Substitute the given value of mass defect and speed of light in above formula:
E =
E =
= Joule.
E=
Thus, nuclear binding energy of an atom is .
<h3>
Answer:</h3>
769.122 cm³
<h3>
Explanation:</h3>
What is volume?
Volume refers to the amount of space of that is occupied by an object.
What are units of measuring volume?
Volume is measured in cubic units. For example cubic meters, cubic centimeters, cubic inches, etc.
How is volume calculated?
Volume is calculated depending on the shape of a solid.
For example,
Volume of a cuboid is length × width × height
Volume of a sphere is 4/3πr³, etc.
In this case;
We are required to calculate the volume of a box whose dimensions are;
16.0 cm × 10.3 cm × 4.667 cm
But;
Volume = l × w × h
Therefore;
Volume of the box = 16.0 cm × 10.3 cm × 4.667 cm
= 769.122 cm³
Thus, the volume of the box is 769.122 cm³