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3 years ago

The equilibrium constant for the reaction:

Chemistry

1 answer:

Scrat [10]3 years ago

5 0

Answer:

1. NO and Br₂

2. 77

3. 8.8

Explanation:

Let's consider the following reaction.

2 NO(g) + Br₂(g) ⇄ 2 NOBr(g)

The equilibrium constant for this reaction is:

$Kc_{1}=\frac{[NOBr]^{2}}{[NO]^{2}[Br_{2}]} =1.3 \times 10^{-2}$

1. At this temperature does the equilibrium favor NO and Br₂, or does it favor NOBr?

Since Kc₁ < 1, the reactants are favored, that is, NO and Br₂.

2. Calculate Kc for 2 NOBr(g) ⇄ 2 NO(g) + Br₂(g)

The equilibrium constant is:

$Kc_{2}=\frac{[NO]^{2}[Br_{2}]}{[NOBr]^{2}} =\frac{1}{Kc_{1}} =77$

3. Calculate Kc for NOBr(g) ⇄ NO(g) + 1/2 Br₂(g)

The equilibrium constant is:

$Kc_{3}=\frac{[NO][Br_{2}]^{1/2} }{[NOBr]} =\sqrt{\frac{[NO]^{2}[Br_{2}]}{[NOBr]^{2}}} =\sqrt{Kc_{2}} =8.8$

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3 years ago

Carbon disulfide burns in oxygen to yield car- bon dioxide and sulfur dioxide according to the chemical equation cs2(l) 3 o2(g)

vampirchik [111]

Answer: Oxygen is the limiting reagent.

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As can be seen from the given balanced equation:

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3 years ago

An object with a mass of 4.0 kg has a force of 12.0 newtons applied to it. What is the resultant acceleration of the object?

Zigmanuir [339]

Answer:

3m/s²

Explanation:

Force applied to an object can be calculated thus;

F = ma

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F = force applied (Newtons)

m = mass of substance (kg)

a = acceleration (m/s²)

According to the information provided in this question, F = 12.0 newtons, m = 4.0 kg, a = ?

Derived from F = m.a

We have; a = F/m

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3 years ago

Determine the energy of the electron in the 1s orbital of a helium ion (He+ )

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He Rydberg formula can be extended for use with any hydrogen-like chemical elements.
1/ λ = R*Z^2 [ 1/n1^2 - 1/n2^2] 
where 
λ is the wavelength of the light emitted in vacuum; 
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Z is the atomic number, for He, Z =2; 
n1 and n2 are integers such that n1 < n2 
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c = speed of light = 2.998 x 10^8 m s-1 
E = (6.626x10^-34*2.998 x 10^8)/(2.278*10^-8) = 8.72*10^-18 J ion-1 
Can convert this value to kJ mol-1: 
(8.72*10^-18*6.022 x 10^23)/1*10^3 = 5251 kJ mol-1 
Lit value: RP’s secret book: 5240.4 kJ mol-1 (difference is due to a small change in R going from H to He+) 
So energy of the 1s e- in He+ = -5251 kJ mol-1

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3 years ago

Significant figures are a measure of __________. an precise and accurate answer. the true value of a measurement. accuracy. prec

34kurt

Answer:

Significant figures are a measure of precision.

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Any experimental measurement is inaccurate and must be expressed with its significant figures.

In this way, significant figures express the precision of a measuring tool.

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3 years ago