Answer:
K = 151.9422481
Step-by-step explanation:
At the end of year 10, your perpetuity is worth 100/i
(1) is worth 90×s_{10%i}
So if you set them equal you get 90*[(1+i)^10 - 1]/i = 100/i or [(1+i)^10 - 1] = 10/9 or (1+i)^10 = 19/9 or i = 0.077583937
So now the question compare (1) to (2), at t = 0
(1) is worth 90×a_{10%i} = 90(1 - 1/(1.077583937)^10)/0.077583937 = 610.5441743
(2) is worth K×a_{5%i} = 4.018264714×K
Therefore K = 151.9422481
0.70 is the answer because 0.70=70 tenths.
We use the Pythagorean theorem
x^2=7^2+24^2
x^2=49+576
x^2=625
x=sqrt(625)=25
Answer:
I think the answer is B(3,4).
Step-by-step explanation:
It is that answer because that answer is the only one that stops with and x factor and a y factor.
