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nexus9112 [7]
3 years ago
6

‼️please help ASAP.

Mathematics
1 answer:
USPshnik [31]3 years ago
6 0
Try to do them on math -way
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Figure ABCD is transformed to figure A prime B prime C prime D prime, as shown: A coordinate grid is shown from negative 5 to 0
Bess [88]

Answer:

i need this answer too

7 0
3 years ago
Multiply
Cloud [144]

Answer:

12 x^4 + 18 x^3 - 9 x^2 thus D is the correct answer.

Step-by-step explanation:

Expand the following:

3 x^2 (4 x^2 + 6 x - 3)

3 x^2 (4 x^2 + 6 x - 3) = 3 x^2 (4 x^2) + 3 x^2 (6 x) + 3 x^2 (-3):

3 4 x^2 x^2 + 3 6 x^2 x - 3 3 x^2

3 (-3) = -9:

3 4 x^2 x^2 + 3 6 x^2 x + -9 x^2

3 x^2×6 x = 3 x^(2 + 1)×6:

3 4 x^2 x^2 + 3×6 x^(2 + 1) - 9 x^2

2 + 1 = 3:

3 4 x^2 x^2 + 3 6 x^3 - 9 x^2

3×6 = 18:

3 4 x^2 x^2 + 18 x^3 - 9 x^2

3 x^2×4 x^2 = 3 x^4×4:

3×4 x^4 + 18 x^3 - 9 x^2

3×4 = 12:

Answer:  12 x^4 + 18 x^3 - 9 x^2

6 0
3 years ago
Seis manzanas y 8 peras cuestan $26. ¿Cuanto cuesta cada pera y cada manzana sabiendo que cada manzana cuesta el triple de lo qu
Rom4ik [11]

Usando un sistema de ecuaciones, se encuentra que

  • Cada manzana cuesta $3.
  • Cada pera cuesta $1.

-----------------------

  • Un sistema de ecuaciones soluciona esta pergunta.
  • El custo de una manzana es x.
  • El custo de una pera es y.

-----------------------

  • <u>Seis manzanas y 8 peras cuestan $26</u>, o sea, 6x + 8y = 26
  • <u>Cada manzana cuesta el triple de cada pera</u>, o sea, x = 3y

-----------------------

Primero, encontramos el cuesto de una pera, substituyendo la segunda en la primera ecuación.

6x + 8y = 26

6(3y) + 8y = 26

18y + 8y = 26

26y = 26

y = \frac{26}{26}

y = 1

Cada pera cuesta $1.

-----------------------

<u>Cada manzana cuesta el triple de cada pera</u>, o sea, x = 3y = 3(1) = 3.

Cada manzana cuesta $3.

Se encuentra um problema similar en brainly.com/question/24646137

6 0
2 years ago
The steak is priced at 4 pounds for $2. How much is the steak per pound?
grin007 [14]
The answer is 2 pounds for $1 because you divide 4 by 2 then divide 2 by 2 so 2 pounds for $1.
7 0
2 years ago
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(2y-1)(4y-3) What is the answer to this?
Likurg_2 [28]
(2y-1)(4y-3)=2y\cdot4y+2y\cdot(-3)-1\cdot4y-1\cdot(-3)\\\\=8y^2-6y-4y+3=8y^2-10y+3
4 0
3 years ago
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