<u>The Concept:</u>
We are given the density of a sample of the metal = 11.4 grams / cm³
and we need to find the volume occupied by a sample of 30.5 grams
For this solution, we will use dimensional analysis
from the given information, we can also say that the density of the metal is:
1 cm³ / 11.4 grams
If we multiply this value by 30.5 grams, the 'grams' in the numerator and the denominator will cancel out and we will be left with the volume occupied by 30.5 grams of the metal
<u>Solving for the volume:</u>
X 30.5 grams = (30.5 / 11.4) cm³
Volume of 30.5 grams of the sample = 2.68 cm³
Answer:
Option D. Saturated alkane
Explanation:
To know which option is correct, it is important that we know what saturated and unsaturated compounds are in this context.
Saturated hydrocarbons are compounds which has only carbon to carbon single bonds (C–C) in its chain. A very good example of such compound is the Alkanes.
Unsaturated hydrocarbons are compounds which has either a carbon to carbon double bond (C=C) or a carbon to carbon triple bond (C≡C) in its chain. Examples of such compounds include alkenes and alkynes.
Now, let us answer the question given above bearing the meaning of saturated and unsaturated compounds in mind.
The compound given above contains only carbon to carbon (C–C) single bond.
Therefore, the compound is a saturated alkane.
Answer:
Yes
Explanation:
It is balanced because On both sides there are 4 hydrogen atoms and 2 oxygen atoms, or in this case, 2 molecular hydrogens and 1 molecular oxygen, which made hydric acid, aka dihydrogen monoxide, or universally, as water.
The balanced chemical equation for the following equation is:
Ca(OH)
2
+CO
2
⟶CaCO
3
+H
2
O
Answer:
0.071L
Explanation:
From the question given, we obtained the following data:
Molarity of HCl = 2.25 M
Mass of HCl = 5.80g
Molar Mass of HCl = 36.45g/mol
Number of mole of HCl =?
Number of mole = Mass /Molar Mass
Number of mole of HCl = 5.8/36.45 = 0.159mole
Now, we can obtain the volume required as follows:
Molarity = mole /Volume
Volume = mole /Molarity
Volume = 0.159mole/ 2.25
Volume = 0.071L
