I don’t know what the question is asking
Answer:
6.68 X 10^-11
Explanation:
From the second Ka, you can calculate pKa = -log (Ka2) = 6.187
The pH at the second equivalence point (8.181) will be the average of pKa2 and pKa3. So,
8.181 = (6.187 + pKa3) / 2
Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11
Answer:
I don’t know this answer sorry
Explanation:
During photosynthesis plant release
<span>C 6 H 12 O 6 + 6 H 2 O + 6 O 2
the gas is 6O2
</span>
