Answer:
Explanation:
The<em> heat</em> to <em>vaporize</em> a l<em>iquid</em> is equal to the amount of liquid in moles multiplied by the specific <em>heat of vaporiztion</em> per mole.
First, calculate the number of moles in 35.5g of <em>butane</em>.
- Molar mass of butane: 58.124 g/mol
- Number of moles = mass in grams/molar mass
- Number of moles = 35.5g / 58.124g/mol = 0.6107632mol
Now, calculate the heat to vaporize that amount of <em>liquid butane</em>:
- Heat = number of moles × specific heat of vaporization
- Heat = 0.6107632mol × 21.3kJ/mol = 13.0 kJ
The answer must be reported with 3 significant figures.
In the above equation, the product formed is :
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