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Nastasia [14]
3 years ago
10

received a bag of his favorite candies, for Teacher Appreciation Week, 5 were Hersey's, 3 were Butterfingers, 7 were crunched, a

nd 6 were kitkats. If he selects one at random and then another, after eating the first one, what are his chances of selecting a Butterfinger and then a Hersey? Be sure to reduce to the lowest terms.
Mathematics
1 answer:
dlinn [17]3 years ago
3 0

Answer:i dont know

ok

i just need points

Step-by-step explanation:

done ??

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What is the equation for the line with a slope of - 2/3 that passes through (0, -2)
viktelen [127]

Answer:

y= -2/3x-2

Step-by-step explanation:

Since we have a point and a slope, we can use the point slope formula

y-y_{1} =m(x-x_{1})

m is the slope. In this case, m is -2/3

y1 is the y coordinate of the point. In this case, it is -2

x1 is the x coordinate. In this case it is 0.

We can substitute these values into the formula

y- -2= -2/3(x-0)

Distribute -2/3

y+2 = -2/3*x + -2/3*0

y+2= -2/3x+0

Subtract 2 from both sides. We want to get y by itself. This is because we want our line to be in y=mx+b form.

y+2-2= -2/3x+0-2

y= -2/3x -2

5 0
3 years ago
What is the prime factorization of the number 45
ohaa [14]
..........................

7 0
3 years ago
Read 2 more answers
If x = -5 and y = x + 4, what ordered pair represents the solution? A. (5, -1) B. (-5, -1) C. (5, 1) D. (4, 4)
tekilochka [14]
B.) would be correct
(x,y)
x=-5
y=x+4
y=(-5)+4
y=-1
(-5,-1)
3 0
3 years ago
Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and
Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling:

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.85}{\sqrt{35}} = 0.1437

P(sample average sediment density is at most 3.00)

P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)

Calculation the value from standard normal z table, we have,  

P(x \leq 3.00) = 0.918

0.918 is the probability that the sample average sediment density is at most 3.00

4 0
3 years ago
Please help. I really need it.
Fed [463]
It’s b and d because when simplified they’re both 25/1
6 0
3 years ago
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