Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
The correct answer is D. Since the polygons are /similar/ and not /congruent/, C is not necessarily true.
Hope this helps.
This is an altitude. Shown by the right angle on the side opposite the point.
Answer:
it's ax+b form answer is Q(x-2)=4x-6
Step-by-step explanation:
ax+b=Q(x),Q(x-2)=a(x-2)+2
Q(3x)=a(3x)+b=12x+2, 3a=12 =>a=4,b=2
the original q of x is 4x+2
Q of x-2 =4(x-2)+2=4x-8+2=4x-6
Answer:
x^2+x-4
Step-by-step explanation:
(f-g)=(x^2+1)-(5-x)
=x^2+1-5+x
=x^2+x-4
