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3 years ago

In a family with 2 children, excluding multiple births, what is the probability of having a boy and a girl in any order?

Mathematics

2 answers:

Greeley [361]3 years ago

8 0

50% because 100% divided by 2 children would be 50% per child.

ioda3 years ago

4 0

50% because it can either girl or boy first. I hope i helped

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If the Federal Reserve sets the reserve rate to 5%, what is the resulting money

sesenic [268]

Answer:

To get this answer you’d just divide 5% by 100, and you’d get 0.05. I hope this helps!

Step-by-step explanation:

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3 years ago

You get paid $10 an hour. In order to make $210, you need to work 21 hours. If you work the same amount of hours for four days a

Citrus2011 [14]

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3 years ago

You have two cubes that you filled with water to make ice cubes. The first cube has a side length of 3 units. The second cube ha

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3 years ago

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construct a 90% confidence interval of the population proportion using the giver information x=74 n=150

FrozenT [24]

Answer:

The 90% confidence interval of the population proportion is (0.43, 0.56).

Step-by-step explanation:

The (1 - α)% confidence interval for population proportion p is:

$CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The information provided is:

X = 74

n = 150

Confidence level = 90%

Compute the value of sample proportion as follows:

$\hat p=\frac{X}{n}=\frac{74}{150}=0.493$

Compute the critical value of z for 90% confidence level as follows:

$z_{\alpha/2}=z_{0.10/2}=z_{0.05}=1.645$

*Use a z-table.

Compute the 90% confidence interval of the population proportion as follows:

$CI=\hat p\pm z_{\alpha/2}\ \sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.493\pm 1.645\times \sqrt{\frac{0.493(1-0.493)}{150}}\\\\=0.493\pm 0.0672\\\\=(0.4258,\ 0.5602)\\\\\approx (0.43,\ 0.56)$

Thus, the 90% confidence interval of the population proportion is (0.43, 0.56).

3 0

3 years ago

What is 25%of395 thanks

tia_tia [17]

98.75
Just do 0.25 (25%) times 395
its the same as doing 395 divided by 25

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3 years ago

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