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solmaris [256]
3 years ago
14

If a gas has a molecular mass of 44.0, the volume of 88.0 grams of the gas at STP would be ..

Chemistry
1 answer:
Montano1993 [528]3 years ago
3 0
2) 11.2
All you have to do is multiply 44 by 22.4 L, which equals 985.6
Then you divide 985.6 by 88 to get your answer of 11.2 L
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Which base would not effectively deprotonate acetylene? (ch3)2nli ch3och2mgbr lioch3 ch3li kh?
Eva8 [605]

Acetylene has a chemical formula which can be written as:

C2H2

 

We can see that there are two positive ions, H+. Now what deprotonation means is that the H+ is removed from acetylene to form acetylene ion and water. In this case, I believe that the answer would be:

<span>LiOCH3</span>

8 0
3 years ago
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Briefly explain the benefits and consequences of technology.
Elza [17]
Well there are plenty of benefits and consequences.

But one would be the ability to do certain tasks without actually having to do them. A consequence could be on the environment. For example, the use of a car plays a big part on the environment involving smog.

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3 0
4 years ago
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Lodine has a density of 4.94 g
atroni [7]

Answer:

41.2 lb/gal

Explanation:

Step 1: Given data

Density of iodine: 4.94 g/mL

Step 2: Convert the mass to grams

We will use the conversion factor 1 lb = 454 g.

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Step 3: Convert the volume to gal

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6 0
3 years ago
blast furnaces give off many unpleasant and unhealthy gases. If the total air pressure is .99 ATM the partial pressure of carbon
kolbaska11 [484]

Answer:

P_{air}=1.02atm

Explanation:

Hello!

In this case, since the Dalton's law help us to realize that the total pressure of a gas mixture is computed by adding the partial pressure of each composing gas, for the mixture formed by carbon dioxide, oxygen sulfide (should be hydrogen sulfide instead) and air, we can write:

P=P_{CO_2}+P_{H_2S}+P_{air}

Thus, given the total pressure and the partial pressures of both carbon dioxide and hydrogen sulfide, the partial pressure of the remaining air would be:

P_{air}=P_{T}-P_{H_2S}-P_{CO_2}

Therefore, we plug in to obtain:

P_{air}=0.99atm-0.05atm-0.02atm\\\\P_{air}=1.02atm

Best regards!

6 0
3 years ago
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xenn [34]
Endoskeleton
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Change those up for exoskeletons.. pros for cons and cons for pros
3 0
3 years ago
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