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horrorfan [7]
3 years ago
12

The smell of hot food moves faster than the smell of cold food. Which property of gas is responsible for this?

Chemistry
2 answers:
zhenek [66]3 years ago
4 0
The answer would be kinetic energy. :)
Murrr4er [49]3 years ago
4 0

A. the kinetic energy of gas particles is higher in hot food than in cold food.

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You wish to measure the iron content of the well water on the new property you are about to buy. You prepare a reference standar
djverab [1.8K]

1.04 ⨯ 10^{-4} M

<h3>Explanation</h3>

<em>A</em> = <em>ε</em> \cdot l \cdot c by the Beer-Lambert law, where

  • <em>A</em> the absorbance,
  • l the path length,
  • <em>ε</em> the molar absorptivity of the solute, and
  • c concentration of the solution.

<em>A</em> and <em>ε </em>are the same for both solutions. Therefore, l \cdot c is constant; l is inversely proportional to c. The 100 mL sample would have a concentration 1/4.78 times that of the 45.0 mL reference.

The 13.0 mL standard solution has a concentration of 5.17 ⨯ 10^{-4} M. Diluting it to 45.0 mL results in a concentration of 5.17 \times 10^{-4} \times \frac{13.0}{45.0} = 1.494 M.

c is inversely related to l for the two solutions. As a result, c₂ = c_1 \cdot \frac{l_1}{l_2} = 1.494 \times 10^{-4} \times \frac{1}{4.78} = 3.126 M.

The 30.0 mL sample has to be diluted by 30.0 / 100.0 times to produce the 100.0 mL solution being tested. The 100.0 mL solution has a concentration of 3.126 M. Therefore, the 30.0 mL solution has a concentration of 3.126 \times \frac{100.0}{30.0} = 1.04 ⨯ 10^{-4} M.

6 0
3 years ago
The half-life of radioactive substance is 2.5 minutes. what fraction of the origional radioactive remains after 10 mins
saul85 [17]
The answer is 1/16.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. (1/2)^{n} = x,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample

2. t_{1/2} = \frac{t}{n}
where:
<span>t_{1/2} - half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
So, we know:
t = 10 min
<span>t_{1/2} = 2.5 min

We need:
n = ?
x = ?
</span>
We could first use the second equation to calculate n:
<span>If:
t_{1/2} = \frac{t}{n},
</span>Then: 
n = \frac{t}{ t_{1/2} }
⇒ n = \frac{10 min}{2.5 min}
⇒ n=4<span>
</span>
Now we can use the first equation to calculate the remained fraction of the sample.
<span>(1/2)^{n} = x
</span>⇒ x=(1/2)^4
<span>⇒x= \frac{1}{16}</span>
3 0
3 years ago
Gold is alloyed (mixed) with other metals to increase its hardness in making jewelry.
KiRa [710]

Answer:

A) 54.04%

B) 13-karat

Explanation:

A) From the problem we have

<em>1)</em> Mg + Ms = 9.40 g

<em>2)</em> Vg + Vs = 0.675 cm³

Where M stands for mass, V stands for volume, and g and s stand for gold and silver respectively.

We can rewrite the first equation using the density values:

<em>3)</em> Vg * 19.3 g/cm³ + Vs * 10.5 g/cm³ = 9.40

So now we have<em> a system of two equations</em> (2 and 3) <em>with two unknowns</em>:

We <u>express Vg in terms of Vs</u>:

  • Vg + Vs = 0.675 cm³
  • Vg = 0.675 - Vs

We <u>replace the value of Vg in equation 3</u>:

  • Vg * 19.3 + Vs * 10.5 = 9.40
  • (0.675-Vs) * 19.3 + Vs * 10.5 = 9.40
  • 13.0275 - 19.3Vs + 10.5Vs = 9.40
  • -8.8 Vs + 13.0275 = 9.40
  • <u>Vs = 0.412 cm³</u>

Now we <u>calculate Vg</u>:

  • Vg + Vs = 0.675 cm³
  • Vg + 0.412 cm³ = 0.675 cm³
  • Vg = 0.263 cm³

We <u>calculate Mg from Vg</u>:

  • 0.263 cm³ * 19.3 g/cm³ = 5.08 g

We calculate the mass percentage of gold:

  • 5.08 / 9.40 * 100% = 54.04%

B)

We multiply 24 by the percentage fraction:

  • 24 * 54.04/100 = 12.97-karat ≅ 13-karat
4 0
3 years ago
1.) What are the two broad categories that elements can be divided into?
hoa [83]

Answer:

1) Metals and nonmentals

2) Elements: Oxygen (O_{2} \\) , Nitrogen (N_{2}

3) Compounds: Carbon Dioxide CO_{2}, Methane CH_{4}, Nitrogen DioxideNO_{2}

Explanation:

5 0
3 years ago
The density of water at 400C is 0.992 g/mL What is the volume of 27.0 g of water at this temperature?
pantera1 [17]

Answer:

Volume of water at this temperature is 27.2 mL

Explanation:

We know that density=\frac{mass}{volume}

Here density of water is 0.992 g/mL

Here mass of water is 27.0 g

So volume=\frac{mass}{density}

                         = \frac{27.0g}{0.992g/mL}

                         = 27.2 mL

7 0
3 years ago
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