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pav-90 [236]
3 years ago
8

Compare and contrast chemical reactions and nuclear reactions in terms of particles involved . Select all the statements that ap

ply Both chemical and nuclear equations are written with equal signs. Nuclear reactions create a difference in the number of protons, neutrons, and electrons after the reaction. A chemical reaction is the rearranging of atoms to form new substances. E=mc^ aleph 2 applies to both chemical and nuclear reactions. In a nuclear reactionparticles can transmute into others. Chemical reactions produce energy on levels comparable to nuclear reactions The total number of protons, neutrons, and electrons stay the same throughout the chemical reaction.

Physics
1 answer:
Anna11 [10]3 years ago
5 0

Answer:

. A chemical reaction is the rearranging of atoms to form new substances. E=mc^ aleph

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Lapatulllka [165]

To solve this problem we will apply the concepts related to the calculation of the speed of sound, the calculation of the Mach number and finally the calculation of the temperature at the front stagnation point. We will calculate the speed in international units as well as the temperature. With these values we will calculate the speed of the sound and the number of Mach. Finally we will calculate the temperature at the front stagnation point.

The altitude is,

z = 20km

And the velocity can be written as,

V = 3530km/h (\frac{1000m}{1km})(\frac{1h}{3600s})

V = 980.55m/s

From the properties of standard atmosphere at altitude z = 20km temperature is

T = 216.66K

k = 1.4

R = 287 J/kg

Velocity of sound at this altitude is

a = \sqrt{kRT}

a = \sqrt{(1.4)(287)(216.66)}

a = 295.049m/s

Then the Mach number

Ma = \frac{V}{a}

Ma = \frac{980.55}{296.049}

Ma = 3.312

So front stagnation temperature

T_0 = T(1+\frac{k-1}{2}Ma^2)

T_0 = (216.66)(1+\frac{1.4-1}{2}*3.312^2)

T_0 = 689.87K

Therefore the temperature at its front stagnation point is 689.87K

6 0
3 years ago
Trong thí nghiệm về giao thoa sóng trên mặt nước gồm hai nguồn kết hợp S1S2 cách nhau 15 cm với dao động với tần số 30Hz. Tốc độ
mojhsa [17]

Answer:

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A 4300-N force from a car's engines produces an acceleration of 3.3 m/s2. What is the mass of the car?
sertanlavr [38]

Answer:The net force acting on the car is 3×103 Newtons

Explanation:

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You are given an unknown solid substance of mass 500 g and you want to estimate its specific heat. unfortunately, you don’t have
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Answer:

Option C) 2,090 J/(mol K)

Explanation:

Data:

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temperature  = 20° C

Density = 789 kg/m³

Equilibrium reading = 429

volume change = 29 ml

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When we experience positive "g forces", it is as if we have become...
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Answer:

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Explanation:

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