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Soloha48 [4]
3 years ago
15

What is KE if mass = 5kg and velocity= 15m/s

Physics
1 answer:
LekaFEV [45]3 years ago
3 0

1/2*m*v

=1/2*5*15^2

=0.5*5*225

=562.5 joule

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A simple harmonic oscillator has amplitude 0.43 m and period 3.9 sec. What is the maximum acceleration?
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Answer:

Maximum acceleration in the simple harmonic motion will be 0.854rad/sec^2              

Explanation:

We have given amplitude of simple harmonic motion is A = 0.43 m

Time period of the oscillation is T = 3.9 sec

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For this we have to find the angular frequency

Angular frequency will be equal to \omega =\frac{2\pi }{T}=\frac{2\times 3.14}{3.9}=1.61rad/sec

Maximum acceleration is given by a_{max}=\omega ^2A=1.61^2\times 0.43=0.854rad/sec^2

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An electric field is produced by the very long, uniformly charged rod drawn above. If the strength of the electric field is E1 a
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Answer: hello the complete question is attached below

answer :

r2 = 4r1

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