Answer:
A.The spring constant for B is one quarter of the spring constant for A.
Explanation:
If spring A oscillates at twice the frequency of spring B, and period is frequency inverted. It means spring B has a period twice of spring A's.

As
, and the 2 springs have the same mass




So A.The spring constant for B is one quarter of the spring constant for A. is the correct answer.
Answer:
For 6.0 eV
0.5 nm, 1.45*10^6 m/s, 6.17*10^10 m/s, 1.45*10^6 m/s
For 600 eV
1.26*10^-3 nm, 2.66*10^8 m/s, 3.37*10^8 m/s, 2.66*10^8 m/s
Explanation:
See attachment for calculation
Answer:
294 mAmps
Explanation:
The two resistors are equal to 22 * 75 / ( 22+ 75) = 17.01 ohm
V = IR
V/R = I
5 / 17.01 = .294 A