Answer:
A. 28.42 m/s
B. 41.21 m
Explanation:
From the question given above, the following data were obtained:
Time (t) to reach the maximum height = 2.90 s
Initial velocity (u) =?
Maximum height (h) =?
A. Determination of the initial velocity of the ball.
Time (t) to reach the maximum height = 2.90 s
Final velocity (v) = 0 m/s (at maximum height)
Acceleration due to gravity (g) = 9.8 m/s²
Initial velocity (u) =?
v = u – gt (since the ball is going against gravity)
0 = u – (9.8 × 2.9)
0 = u – 28.42
Collect like terms
0 + 28.42 = u
u = 28.42 m/s
Thus, the initial velocity of the ball is 28.42 m/s
B. Determination of the maximum height reached by the ball.
Final velocity (v) = 0 m/s (at maximum height)
Acceleration due to gravity (g) = 9.8 m/s²
Initial velocity (u) = 28.42 m/s
Maximum height (h) =?
v² = u² – 2gh (since the ball is going against gravity)
0² = 28.42² – (2 × 9.8 × h)
0 = 807.6964 – 19.6h
Collect like terms
0 – 807.6964 = – 19.6h
– 807.6964 = – 19.6h
Divide both side by – 19.6
h = – 807.6964 / – 19.6
h = 41.21 m
Thus, the maximum height reached by the ball is 41.21 m
