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timofeeve [1]
2 years ago
11

When holes are drilled through the wall of a water tower, water will spurt out the greatest horozontal distance from the hole cl

osest to?
Physics
1 answer:
Mnenie [13.5K]2 years ago
3 0

Bottom of the water tower

Explanation:

When holes are drilled through the wall of a water tower, water will spurt out the greatest horizontal distance from the hole closest to the bottom of the water tower.

This is because the near the bottom of the tower is the greatest compared to other parts of the tower.

  • The pressure increases with depth.
  • As the depth of water increases, the column of water above exerts more pressure on the one below.
  • Therefore, water will spurt out more from the bottom of the tower compared to the top of the tower.

Learn more:

Pressure brainly.com/question/4868239

#learnwithBrainly

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What will be the ME of a machine that produces a 240 N work with a 300
Elden [556K]

Answer:

Efficiency = 80%

Explanation:

Given the following data;

Work output = 240 N

Work Input = 300 N

To find the mechanical efficiency of a machine;

Efficiency = \frac {Out-put \; work}{In-put \; work} * 100

Substituting into the equation, we have;

Efficiency = \frac {240}{300} * 100

Efficiency = 0.8 * 100

Efficiency = 80%

Therefore, the mechanical efficiency of the machine is 80 percent.

3 0
3 years ago
A certain first-order reaction is 58% complete in 95 s. What are the values of the rate constant and the half-life for this proc
guajiro [1.7K]

Answer:

0.005734 s^{-1} and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..

Explanation:

Expression for rate law for first order kinetics is given by:

a_o=a\times e^{-kt}

where,

k = rate constant  

t = age of sample

a_o = let initial amount of the reactant  

a = amount left after decay process  

We have :

a_o=x

a=58\%\times x=0.58x

t = 95 s

0.58x=x\times e^{-k\times 95 s}

\k= 0.005734 s^{-1}

Half life is given by for first order kinetics::

t_{1/2}=\frac{0.693}{k}

=\frac{0.693}{0.005734 s^{-1}}=120.86 s

0.005734 s^{-1} and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..

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Answer:10

Explanation:

You have to do speed divided by time so your answers 10

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