Answer:The highest possible efficiency of this heat engine is 11%
Explanation:
Saturated water temperature at P1, Pressure in Heat addition,
1.1 MPa=185°C +273= 458K
Saturated water temperature at P2, Pressure in Heat rejection,
0.3MPa=133.5°C+ 273=406.5K
The highest possible efficiency of any heat engine is the Carnot efficiency given as
Carnot efficiency, ηmax = 1- (T2/ T1)
1- (406.5K/458K)
1-0.88755=0.112
=11%
4.5m/s you count the number between 6 and 14 and get 9 do 9 divided by 2 and you get 4.5 m/s increase. hope this helps.
1.12 m/s is the velocity. You can get the velocity of a wave by multiplying the frequency and wavelength together. The product is the velocity.
Kinetic energy = 0.5 * m * v²
m mass
v velocity
If the velocity stays the same and the kinetic energy goes down by a factor of 2, the mass must go down by a factor of 2 also.
Poder = (resistencia) x (corrente)²
Poder = (10 ohms) x (5 A)²
<em>Poder = 250 watts </em>(250 Joule por segundo)
2 horas = 7,200 segundos
Energia = (250 joule/seg) x (7,200 seg)
<em>Energia = 1,800,000 Joules</em>