Putting a = 6 and b= 3/2 in eqn. (1) the required equation is:-
x /6 + 2.y/3 = 1. or, x + 4y = 6. Answer.
Volume of a quadrangular pyramid=(1/3)bh
b=base
h=height
b=area of the base=area of a square=8.4 ft * 8.4 ft=70.56 ft²
Pythagoras theorem:
hypotenuse²=leg₁² + leg₂²
data:
hypotenuse=9.6 ft
leg₁=height=h
leg₂=8.4 ft /2=4.2 ft
(9.6 ft)²= h² + (4.2 ft)²
92.16 ft²=h²+17.64 ft²
h²=92.16 ft²-17.64 ft²
h²=74.52 ft²
h=√(74.52 ft²)=8.63 ft.
Volume of this quadrangular pyramid=(1/3)(70.56 ft²)(8.63 ft)=202.9 ft³≈202.3 ft³
Answer: ≈202.3 ft³
Answer:
look it up Answer:
Step-by-step explanation:
Step-by-step explanation:
Answer:
Height = 1 inch
Step-by-step explanation:
area of triangle = 1/2 x base x height
11.5 =1/2 x 23 x height
23/23 = height
height = 1
