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Lemur [1.5K]
3 years ago
8

A swimmer travels from the south end to the north end of a 30.0 m pool in 15.0 s and makes the return trip to the starting posit

ion in 19.0 s. What is the average velocity for the roundtrip?
Physics
1 answer:
JulsSmile [24]3 years ago
8 0

Answer:

Zero

Explanation:

Average velocity is given by:

v=\frac{d}{t}

where

d is the displacement of the trip

t is the time it takes for the trip to complete

In this problem, the net displacement of the swimmer is zero. In fact:

- First, he swims 30.0 m in the north direction

- Then, he travels back (-30.0 m) in the south direction, to the starting position

Since the final position is equal to the starting position, the displacement is zero:

d = 0

And therefore, the average velocity is also zero.

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To determine the heat released by the process of condensation, we simply multiply the amount of the gas that condensed to the latent heat of vaporization. We do as follows:

Heat released = 21 J/g (12.0 g ) = 252 J of heat released
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Answer:

hmm

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Liquid sodium can be used as a heat transfer fluid. Its vapor pressure is 40.0 torr at 633°C and 400.0 torr at 823°C. Calculate
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Answer:

H vaporization = 100.0788 kJ/mol

Explanation:

Use clausius clapyron's adaptation for the calculation of Hvap as:

ln\frac {P_2}{P_1}=\frac {H_{vap}}{R}(\frac {1}{T_1}-\frac {1}{T_2})

Where,

P₂ and P₁ are the pressure at Temperature T₂ and T₁ respectively.

R is the gas constant.

T₂ = 823°C

T₁ = 633°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So, the temperature,

T₂ = (823 + 273.15) K = 1096.15 K

T₁ = (633 + 273.15) K = 906.15 K

P₂ = 400.0 torr , P₁ = 40.0 torr

R = 8.314 J/K.mol

Applying in the formula to calculate heat of vaporization as:

ln \frac {400}{40}=\frac {H_{vap}}{R} (\frac {1}{906.15}-\frac {1}{1096.15})

Solving for heat of vaporization, we get:

H vaporization = 100078.823 J/mol

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<u>H vaporization = 100.0788 kJ/mol</u>

4 0
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marin [14]

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Igneous rocks can be changed into metamorphic rocks when heat and pressure are applied to the rock.

Pressure and heat in the presence of a fluid phase cause metamorphic transformation of a prolith.

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