To answer this
problem, we use the binomial distribution formula for probability:
P (x) = [n!
/ (n-x)! x!] p^x q^(n-x)
Where,
n = the
total number of test questions = 10
<span>x = the
total number of test questions to pass = >6</span>
p =
probability of success = 0.5
q =
probability of failure = 0.5
Given the
formula, let us calculate for the probabilities that the student will get at
least 6 correct questions by guessing.
P (6) = [10!
/ (4)! 6!] (0.5)^6 0.5^(4) = 0.205078
P (7) = [10!
/ (3)! 7!] (0.5)^7 0.5^(3) = 0.117188
P (8) = [10!
/ (2)! 8!] (0.5)^8 0.5^(2) = 0.043945
P (9) = [10!
/ (1)! 9!] (0.5)^9 0.5^(1) = 0.009766
P (10) = [10!
/ (0)! 10!] (0.5)^10 0.5^(0) = 0.000977
Total
Probability = 0.376953 = 0.38 = 38%
<span>There is a
38% chance the student will pass.</span>
The only one that wouldn’t change the y-value is a reflection across the y-axis.
Answer:
6 ft
Step-by-step explanation:
Since the distance between the bottom of the ladder and the wall forms a right angle that is across from the ladder, you can use the Pythagorean Theorem to solve for the value of 'x':
a² + b² = c², where 'a' and 'b' are the legs of the triangle and 'c' is the diagonal or hypotenuse.
Using 8 for 'a' and 10 for 'c':
8² + x² = 10²
64 + x² = 100
Subtract 64 from both sides:
64 - 64 + x² = 100 - 64 or x² = 36
Take the square root of both sides:
√x² = √36
x = 6 ft
Answer:
The estimated amount of metal in the can is 87.96 cubic cm
Step-by-step explanation:
We can find the differential of volume from the volume of a cylinder equation given by
Thus that way we will find the amount of metal that makes up the can.
Finding the differential.
A small change in volume is given by:
So finding the partial derivatives we get
Evaluating the differential at the given information.
The height of the can is h = 26 cm, the diameter is 10 cm, which means the radius is half of it, that is r = 5 cm.
On the other hand the thickness of the side is 0.05 cm that represents dr = 0.05 cm, and the thickness on both top and bottom is 0.3 cm, thus dh = 0.3 cm +0.3 cm which give us 0.6 cm.
Replacing all those values on the differential we get
That give us
Or in decimal value
Thus the volume of metal in the can is 87.96 cubic cm.
