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sergij07 [2.7K]
3 years ago
14

Shhhh Help me and you get Star ratings

Mathematics
2 answers:
san4es73 [151]3 years ago
4 0

Answer: find the measure of <6

Step-by-step explanation:

lidiya [134]3 years ago
4 0

Answer:

Interior angles = 2, 4, 5, 7

Exterior angles = 1, 3, 6, 8

Alternate interior angles = 2 & 7, 5 & 4

Alternate exterior angles = 1 & 8, 6 & 3

<3 = 96*

<5 = 84*

<6 = 96*

Step-by-step explanation:

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Find Y to the nearest degree
inessss [21]

Answer:

The answer is D =35°

Tan inverse of 19/27

4 0
3 years ago
Is this correct? if not please let me know how to solve it
Degger [83]
That is correct.
You have applied the distributive law.
6 0
4 years ago
Read 2 more answers
Can someone thoroughly explain this implicit differentiation with a trig function. No matter how many times I try to solve this,
Anton [14]

Answer:

\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)(1+\sec^2(x-y)(8+x^2))}

Step-by-step explanation:

So we have the equation:

\tan(x-y)=\frac{y}{8+x^2}

And we want to find dy/dx.

So, let's take the derivative of both sides:

\frac{d}{dx}[\tan(x-y)]=\frac{d}{dx}[\frac{y}{8+x^2}]

Let's do each side individually.

Left Side:

We have:

\frac{d}{dx}[\tan(x-y)]

We can use the chain rule, where:

(u(v(x))'=u'(v(x))\cdot v'(x)

Let u(x) be tan(x). Then v(x) is (x-y). Remember that d/dx(tan(x)) is sec²(x). So:

=\sec^2(x-y)\cdot (\frac{d}{dx}[x-y])

Differentiate x like normally. Implicitly differentiate for y. This yields:

=\sec^2(x-y)(1-y')

Distribute:

=\sec^2(x-y)-y'\sec^2(x-y)

And that is our left side.

Right Side:

We have:

\frac{d}{dx}[\frac{y}{8+x^2}]

We can use the quotient rule, where:

\frac{d}{dx}[f/g]=\frac{f'g-fg'}{g^2}

f is y. g is (8+x²). So:

=\frac{\frac{d}{dx}[y](8+x^2)-(y)\frac{d}{dx}(8+x^2)}{(8+x^2)^2}

Differentiate:

=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}

And that is our right side.

So, our entire equation is:

\sec^2(x-y)-y'\sec^2(x-y)=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}

To find dy/dx, we have to solve for y'. Let's multiply both sides by the denominator on the right. So:

((8+x^2)^2)\sec^2(x-y)-y'\sec^2(x-y)=\frac{y'(8+x^2)-2xy}{(8+x^2)^2}((8+x^2)^2)

The right side cancels. Let's distribute the left:

\sec^2(x-y)(8+x^2)^2-y'\sec^2(x-y)(8+x^2)^2=y'(8+x^2)-2xy

Now, let's move all the y'-terms to one side. Add our second term from our left equation to the right. So:

\sec^2(x-y)(8+x^2)^2=y'(8+x^2)-2xy+y'\sec^2(x-y)(8+x^2)^2

Move -2xy to the left. So:

\sec^2(x-y)(8+x^2)^2+2xy=y'(8+x^2)+y'\sec^2(x-y)(8+x^2)^2

Factor out a y' from the right:

\sec^2(x-y)(8+x^2)^2+2xy=y'((8+x^2)+\sec^2(x-y)(8+x^2)^2)

Divide. Therefore, dy/dx is:

\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)+\sec^2(x-y)(8+x^2)^2}

We can factor out a (8+x²) from the denominator. So:

\frac{dy}{dx}=y'=\frac{\sec^2(x-y)(8+x^2)^2+2xy}{(8+x^2)(1+\sec^2(x-y)(8+x^2))}

And we're done!

8 0
3 years ago
What is the positive solution to this equation? 4x2 + 12x = 135​
Bas_tet [7]

Answer:

127/12

Step-by-step explanation:

4 × 2 + 12x = 135

(1. Simplify 4 x 2 to 8.

8 + 12x = 135

(2. Subtract 88 from both sides.

12x= 135 - 8

(3. Simplify 135 - 8 to 127

12x = 127

(4. Divide both sides by 12

x= 127/12

Decimal Form: 10.583333

I think this is the awnser, but don't quote me on that

4 0
3 years ago
Ana is using a photocopier to make
I am Lyosha [343]

Answer:

divide 63 by 3 to get how many copies will be made in 1 min, 63/3= 21

divide 315 to 21 to know how many min it will take= 315/21= 15

It will take 15 min to make 315 copies!

Step-by-step explanation:

Hope this helps!!!

7 0
3 years ago
Read 2 more answers
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