In the given you wrote -2, whereas it should be -2i
z = a + bi and in trigo form | z |.(cos Ф + i.sin Ф).
z = 0 -2i → | z |.(cos Ф + i.sin Ф)
Now let's calculate z:
z² = a²+b² → z² = 0² (-2.i)² → z = -2(i)² →z= -2(-1) → z = |2|
tan Ф = b/a = -2/0 → tan Ф → - ∞ ↔ Ф = -90° or Ф = 270°
then the - 2 I ↔ |2|(cos 270° + i.sin 270°)
Answer:
Hey There the Answer to this is x = nickels
y= dimes
x + y = 34
.05x + .10y= $1.90
-.10x - .10y = -3.40
-.05x + .10y = 1.90
-.05x = -1.50
x = 30 nickels
30 + y = 34
y = 4 dimes
(3,4) And that you get the answer.
Hope it helps!
Answer:
Step-by-step explanation:
All of these numbers can be divided by 2, 3, 5, 7, 11, 13...
There is no whole number if you want to divide each number.
121 only goes into 1, 11, and 121. No other numbers have 11
45/2 = 22.5
45/3 = 15
45/5 = 9
2470/2 = 1235
2470/3 = 823.33333...
2470/5 = 494
121/2 = 60.5
121/3 = 40.33333...
121/5 = 24.2
Option C:
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Solution:
Area of the square paper = 
sq. cm
Area of the square corner removed = 16 sq. cm
Let us find the area of the remaining paper.
Area of the remaining paper = Area of the square paper – Area of the corner
Area of the remaining = 
= 
Using algebraic formula: 
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Hence (3x – 4)(3x + 4) represents area of the remaining paper in square centimeters.
Answer:
Step-by-step explanation:
The directrix is a vertical line, so the parabola is horizontal. The focus lies to the left of the directrix, so the parabola opens to the left.
For a left-opening parabola:
x = a(y-k)²+h,
a < 0,
vertex (h,k)
focal length p = 1/|4a|
focus (h-p, k)
directrix: x=h+p
Apply your data
focus (1,-4)
directrix x=2
vertex (1.5,-4).
focal length p = 0.5
a = -1/|4p| = -½
x = -½(y-2)²+ ½
