Answer:
x = (-5 ± 2√10) / 3
Step-by-step explanation:
5 − 10x − 3x² = 0
Write in standard form:
-3x² − 10x + 5 = 0
Solve with quadratic formula:
x = [ -b ± √(b² − 4ac) ] / 2a
x = [ -(-10) ± √((-10)² − 4(-3)(5)) ] / 2(-3)
x = [ 10 ± √(100 + 60) ] / -6
x = (10 ± 4√10) / -6
x = (-5 ± 2√10) / 3
Answer:
x=
Step-by-step explanation:
Q= illumination
I = intensity
Q= I/d^2
Q_total = 
= 
now Q' = 0
⇒I
x=![\frac{16}{\sqrt[3]{2}+1 }](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7B%5Csqrt%5B3%5D%7B2%7D%2B1%20%7D)
[/tex]
x=
is the required point
Answer:
3boxes
Step-by-step explanation:
1st we should know the number of cookies
7*5=35
Divide the total of cookies to cookies per box 35/12=2 11/12
2 boxes and 11 cookies remaning (they need an extra box)= 3 boxes
Answer:
(50,55,60,....)
Step-by-step explanation:
Given that a health insurance plan has a $50 enrollment fee and a copayment of $5 for each doctor visit.
The function f(x) = 5x + 50 gives the cost of x doctor visits
Here x is the no of visits.
No of visits is an independent variable while f(x) total cost is a dependent variable on x
slope = 5 which indicates for each visit extra, extra cost is 5 dollars
Enrollment fee = 50 = fixed cost
Hence domain would be
x =0,1,2,3.....
So range is
(50,55,60,....)
Prime factors are factors of a composite number that are indivisible except by the number 1 or the number itself. The answers to your questions are the following:
1. Yes, it is possible especially for very large numbers.
2&3. No, because as mentioned previously, the default prime factors of numbers are 1 and the number itself. For example, 2 is a prime number. Its factors are 1 and 2.
4. Prime factorization are useful in fields of encryption. They make use of the basic prime numbers for the arithmetic modulus with the general equation: n=pq.