All categories

3 years ago

According to the text, which amino acid(s) contains a side chain..

Chemistry

2 answers:

STatiana [176]3 years ago

4 0

Answer:

(b) that is hydrophobic

Explanation:

e.g, alanine

Cause, Alanine possess hydrophobic side chain and the most appropriate answer is (d) part......

Alanine is an aliphatic amino acid, because the side-chain connected to the a-carbon atom is a methyl group (-CH3), alanine is the simplest a-amino acid after glycine. The methyl side-chain of alanine is non-reactive and is therefore hardly ever directly involved in protein function...

Hope it helps....

solniwko [45]3 years ago

3 0

Answer:

(b) that is hydrophobic

Explanation:

e.g, alanine

Cause, Alanine possess hydrophobic side chain and the most appropriate answer is (d) part......

Alanine is an aliphatic amino acid, because the side-chain connected to the α-carbon atom is a methyl group (-CH3), alanine is the simplest α-amino acid after glycine. The methyl side-chain of alanine is non-reactive and is therefore hardly ever directly involved in protein function..

Hope it will help you☺☺☺☺☺

You might be interested in

Identify the compound with the smallest dipole moment in the gas phase. identify the compound with the smallest dipole moment in

stepladder [879]

Without solving for the dipole moment, we can easily determine which among the common gases has the smallest dipole moment just by determining the differences in their electronegativity. The greater the difference in the electronegativity, the higher is the value of the dipole moment.

From the given above, there are obvious differences between the electronegativity between the atoms composing LiF, ClF, and HF. For Cl2, since this is the same molecule then, the difference in the electronegativity is zero.

Answer: Cl2.

3 0

3 years ago

weather balloon is filled with helium to a volume of 340 L at 30 ∘C and 751 mmHg . The balloon ascends to an altitude where the

valentinak56 [21]

Answer: Thus the volume of the balloon at this altitude is 419 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 751 mm Hg

$P_2$ = final pressure of gas = 495 mm Hg

$V_1$ = initial volume of gas = 340 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $30^oC=273+30=303K$

$T_2$ = final temperature of gas = $-27^oC=273-27=246K$

Now put all the given values in the above equation, we get:

$\frac{751\times 340}{303}=\frac{495\times V_2}{246}$

$V_2=419L$

Thus the volume of the balloon at this altitude is 419 L

8 0

3 years ago

What type of property can you observe or measure <br> without chaning the substance

galina1969 [7]

You can observe physical properties using your 5 senses

7 0

3 years ago

Read 2 more answers

The compound NaOH dissolves in water to yield ?

Lunna [17]

<span>Hydroxide ions as the only negative ions</span>

7 0

3 years ago

Combustion analysis of a 13.42-g sample of estriol (which contains only carbon, hydrogen, and oxygen) produced 36.86 g CO2 and 1

meriva

Answer:

C18H24O3

Explanation:

Step 1:

Data obtained from the question. This include the following:

Mass of estriol = 13.42g

Mass of CO2 = 36.86g

Mass of H2O = 10.06g

Molar mass of estriol = 288.38g/mol

Step 2:

Determination of the mass of Carbon (C), Hydrogen (H) and Oxygen (O) present in the compound. This is illustrated below:

For Carbon, C:

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of C in CO2 = 12/44 x 36.86 = 10.05g

For Hydrogen, H:

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of H in H2O = 2/18 x 10.06 = 1.12g

For Oxygen, O:

Mass of O = 13.42 – (10.05 + 1.12) = 2.25g

Step 3:

Determination of the empirical formula for estriol. This is illustrated below:

C = 10.05g

H = 1.12g

O = 2.25g

Divide by their molar mass

C = 10.05/12 = 0.8375

H = 1.12/1 = 1.12

O = 2.25/16 = 0.1406

Divide by the smallest i.e 0.1406

C = 0.8375/0.1406 = 6

H = 1.12/0.1406 = 8

O = 0.1406/0.1406 = 1

Therefore, the empirical formula for estriol is C6H8O

Step 4:

Determination of the molecular formula for estriol. This is illustrated below:

Molecular formula is simply a multiple of the empirical formula i.e

Molecular formula => [C6H8O]n

[C6H8O]n = 288.38g/mol

[(12x6) + (8x1) + 16]n = 288.38

[72 + 8 + 16]n = 288.38

96n = 288.38

Divide both side by 96

n = 288.38/96 = 3

Molecular formula => [C6H8O]n

=> [C6H8O]n

=> [C6H8O]3

=> C18H24O3

Therefore, the molecular formula for estriol is C18H24O3

4 0

3 years ago