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Diano4ka-milaya [45]
4 years ago
9

A diagram of a closed circuit with power source on the left labeled 12 V, a resistor on the top labeled 10 Ohms, a resistor on t

he right labeled 8.0 Ohms and a resistor on the bottom labeled 6.0 Ohms.
Use the circuit diagram to determine the voltage drop across the 8 Ω resistor.


Answer is 4

Physics
2 answers:
Vlada [557]4 years ago
7 0

Answer:

4

Explanation:

zalisa [80]4 years ago
6 0

Answer:

7.5 A

6.0 A

5.0 A

Explanation:

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When a pendulum is swinging, the velocity is highest at which point?
Tems11 [23]
At the center, when the bob is hanging straight down

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3 years ago
A particle accelerator fires a proton into a region with a magnetic field that points in the x-direction. (a) If the proton is m
iVinArrow [24]

Answer:

<em>The magnitude of the magnetic field will act in a direction towards me.</em>

<em></em>

Explanation:

When a charged particle enters a magnetic field, it is deflected. The direction of travel of the particle is deflected, but the kinetic energy of the particle is not affected. <em>The force experienced by a charged particle as it enters a magnetic field that acts perpendicular to the path of the velocity of the particle, will produce a force that is perpendicular to both the direction of travel of the particle and the direction of the magnetic field.</em> In this case, the proton moves in the y-direction, the magnetic field is in the x-direction, therefore the force experienced by the particle will be towards me.

7 0
3 years ago
You plan to take a trip to the moon. Since you do not have a traditional spaceship with rockets, you will need to leave the eart
hichkok12 [17]

Answer:

v = 3.5 \times 10^5 m/s

Explanation:

At some distance from the Earth the force of attraction due to moon is balanced by the force due to Moon

so we will have

\frac{GM_em}{r^2} = \frac{GM_m}{(d-r)^2}

now we have

\frac{d - r}{r} = \sqrt{\frac{M_m}{M_e}}

\frac{3.844\times 10^8 - r}{r} = \sqrt{\frac{7.36 \times 10^{22}}{5.9742\times 10^{24}}}

so we will have

r = 3.46 \times 10^8 m

Now by energy conservation

-\frac{GM_e}{R_e} - \frac{GM_m}{d - (R_e + R_m)} + \frac{1}{2}v^2 = -\frac{GM_e}{r} - \frac{GM_m}{d - r}

-6.26 \times 10^{8} - 13046 + \frac{1}{2}v^2 = -1.15 \times 10^6 - 1.28 \times 10^5

v = 3.5 \times 10^5 m/s

7 0
3 years ago
Question:
valkas [14]

Answer:

the answer is true.

Explanation:

hope it will help you

5 0
3 years ago
Read 2 more answers
Please help with #8... Thanks in advance
schepotkina [342]
If the acceleration is constant, and the starting velocity is zero, the relationship between the acceleration of a falling body (a), the time it takes to fall (t), and instantaneous velocity when it hits the ground (v) is:

the general equation of acceleration is:

vf = vi + at

assuming the initial velocity (vi) is zero, the equation becomes:

vf = at 

v = at
6 0
3 years ago
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