The answer are both:
x=2+4i,2-4i
If we do the division we get x^2 + 3/x-2
there will be an a vertical asymptote at x = 2 but no horizontal asymptote
An equation without exponents and two variables, is typically a straight line. All the points on the line with integer coordinates are solutions of the equation. Since x and y have to be positive as well, there aren't that many solutions.
Let's see where the line crosses the x-axis, it is where y=0:
x/0.5 + 0 = 18, so x=9 at the intercept. y=0 there, so this is a point on the line, but not a solution to the question (y was supposed to be positive).
Possible values for x are thus limited to 1,2,3,4,5,6 and 7. You can try them all (ie., solve the equation with them) and see for which x values the y is also positive and integer.
You will find that x=4, y=2 is the only pair that satisfies these conditions.
Answer:
0.08
Step-by-step explanation:
Please use parentheses to indicate which operations must be done first. I 'm choosing to believe that you meant 7^(3x-1) and 5^(x-1).
Taking the common log of both sides, we get:
(3x-1)log 7 = (x-1)log 5
Then 3x·log 7 - log 7 = x log 5 - log 5
Grouping the x terms:
x(3·log 7 - log 5) = log 7 - log 5. We combine log 7 and log 5, obtaining log (7/5).
Then x(3·log 7 - log 5) = log (7/5).
Solving for x:
log (7/5)
x = ---------------------
3·log 7 - log 5
0.1461
x = ------------- = 0.08
1.0363
This agrees with the 3rd answer choice.
538 x 100 = 53,800
Therefore the product is 53,800.