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solong [7]
3 years ago
8

I dont really understand this question, can anyone help me out?

Mathematics
2 answers:
Aloiza [94]3 years ago
5 0
Complementary angles add up to 90 degrees while supplementary angles will add up to 180 degrees.

1) ABC & NMP
2) EFG & RST
valentinak56 [21]3 years ago
3 0

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Angles.

Complementary angles sum up together to become 90°.

Supplementary Angles sum up together to become 180°.

hence,

1.) Ans ==>Angle ABC and Angle NMP

2.) Ans ==> angle ABC and angle EFG

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6y+12=-2x <br> x+3y=-6 <br> In y form
Vlada [557]

Answer:

  both equations reduce to y = -1/3x -2

Step-by-step explanation:

In each case, subtract the term not containing y and divide by the coefficient of y.

1.  6y = -2x -12 . . . . 12 was subtracted from both sides

  y = -1/3x -2 . . . . . . the equation was divided by 6

__

2. 3y = -x -6 . . . . . . x was subtracted from both sides

  y = -1/3x -2 . . . . . the equation was divided by 3

4 0
3 years ago
Plz anyone help for points
emmainna [20.7K]

Answer:

B. 1,188 cubic units

Step-by-step explanation:

First find the area of the base

A = 1/2b*h (this would only be half the base so our formula would be)

A = b*h (Now enter values)

A = (9)(6)

A = 54 (now plug this into the volume formula)

V = Ab * h

V = (54)(22)

V = 1,188 cubic units

6 0
3 years ago
Write the congruency statement for the triangles. _______In triangles MNO and JKL, there are two congruent sides and included an
mafiozo [28]

Answer:

ΔJKL ≅ ΔMNO by SAS

Step-by-step explanation:

The question is incomplete, the question is as following:

ΔMNO is shown.

Which Δ below can be shown to be congruent to ΔMNO with only the given information?

Name the postulate that justifies your answer (SAS, AAS, HL, ASA or SSS).

Write the congruency statement for the triangles.

And see the attached figure which represent ΔMNO

==========================================================

Check the given options to see which triangle from the option will be congruent to ΔMNO

1. In triangles MNO and ABC, there are two congruent sides and non-included angle - which mean (angle - side - side)

The (angle - side - side) Postulate does not exist because an angle and two sides does not guarantee that two triangles are congruent.

2. In triangles MNO and DEF, there are two congruent sides - there is not enough information

3. In triangles MNO and GHI, there are three congruent angles - which mean AAA (angle - angle - angle)

The AAA Postulate does not exist because an angle and two sides does not guarantee that two triangles are congruent. This postulate is used to prove the similarity between the triangles.

4. In triangles MNO and JKL, there are two congruent sides and included angle - SAS (side - angle - side)

MN ≅ JK , MO ≅ JL , ∠M ≅ ∠J

5 0
3 years ago
Evaluate the following for g(0).g(x)=-9x-15<br>​
Karolina [17]
G(x)= -9(0)-15
G(x)= -15
The answer is -15
6 0
3 years ago
A triangular playground has sides that are lengths 2x feet, x-1 feet and x feet. If the perimeter of this playground is 27 feet,
Keith_Richards [23]

Answer:

The lengths of the sides of the playground are 14 feet, 6 feet, 7 feet

Step-by-step explanation:

At first, let us find the perimeter of the playground

∵ Perimeter of a triangle is P = S1 + S2 + S3

∵ The sides of the triangular playground are (2x) ft, (x - 1) ft, and x ft

∴ S1 = 2x, S2 = x - 1, S3 = x

→ Substitute them in the rule of the perimeter above

∵ P = 2x + x - 1 + x

→ Add the like terms

∴ P = (2x + x + x) - 1

∴ P = 4x - 1

∵ The perimeter of this playground is 27 feet

∴ P = 27

→ Equate the two values of P

∴ 4x - 1 = 27

→ Add 1 to both sides

∴ 4x - 1 + 1 = 27 + 1

∴ 4x = 28

→ Divide both sides by 4

∵ \frac{4x}{4} = \frac{28}{4}

∴ x = 7

→ Substitute the value of x in each side to find their lengths

∵ S1 = 2(7)

∴ S1 = 14 feet

∵ S2 = 7 - 1

∴ S2 = 6 feet

∵ S3 = 7 feet

∴ The lengths of the sides of the playground are 14 feet, 6 feet, 7 feet

7 0
2 years ago
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