Answer:
0.34 x 10^-3 m^3
Explanation:
P1 = 6 x 10^5 N/m^2
T1 = 10 degree C = 10 + 273 = 283 K
T2 = 35 degree c = 35 + 273 = 308 K
Pressure remains constant , P2 = P1
P1 V1 = R T1
V1 = (8.314 x 283) / (6 x 10^5) = 3.92 x 10^-3 m^3
Now, let the Volume is V2
P1 V2 = R T2
V2 = (8.314 x 308) / (6 x 10^5) = 4.26 x 10^-3 m^3
Change in volume, v = V2 - V1 = (4.26 - 3.92) x 10^-3 = 0.34 x 10^-3 m^3
Explanation:
Equation of motion, mathematical formula that describes the position, velocity, or acceleration of a body relative to a given frame of reference.
Answer:
Explanation:
Let a car of m is on an incline bank of angle θ and it is rounding a curve with no friction. We need to find the centripetal force acting on it.
The attached free body diagram shows the car on the banked turn. It is clear that,
In vertical direction,
In horizontal direction,
So, the centripetal force is equal to . Hence, the correct option is (c).
Answer:
No, it is not conserved
Explanation:
Let's calculate the total kinetic energy before the collision and compare it with the total kinetic energy after the collision.
The total kinetic energy before the collision is:
where m1 = m2 = 1 kg are the masses of the two carts, v1=2 m/s is the speed of the first cart, and where v2=0 is the speed of the second cart, which is zero because it is stationary.
After the collision, the two carts stick together with same speed v=1 m/s; their total kinetic energy is
So, we see that the kinetic energy was not conserved, because the initial kinetic energy was 2 J while the final kinetic energy is 1 J. This means that this is an inelastic collision, in which only the total momentum is conserved. This loss of kinetic energy does not violate the law of conservation of energy: in fact, the energy lost has simply been converted into another form of energy, such as heat, during the collision.
Answer:
The smallest integer is n = 4
Explanation:
Using the equation V= Sqrt(F/Linear density)
V= Sqrt(341/0.0120)
V= Sqrt(28416.7)
V= 168.57m/s
Path distance =[ (n +1)/2]lambda
But V= f(Lambda)
n lambda/2 =L
n = f2L/V
n = (20 × 2 × 16.86) / 168.57
n = 4.0007
The smallest integer is n= 4