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rosijanka [135]
3 years ago
5

Calculate the amount of CaO that would be produced when 35.5g of CaCO3 decompose on heating (Ca= 40, O = 16, C = 12, H = 1

Chemistry
1 answer:
DanielleElmas [232]3 years ago
4 0

amount of CaO that would be produced when 35.5g of CaCO3 decompose on heating (Ca= 40, O = 16, C = 12, H = 1

just put the values to have answer

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How many capsules containing 75mg of Tamiflu could be produced from 155g of star anise.?
jeyben [28]
From the question you will find that:
one capsule of tamiflu is obtained from 2.6 g of star anise.
1 capsule   = 2.6 g tamiflu
? capsules = 155 g tamiflu
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Which statements are true about Figure I and Figure II below? (Check all that apply)
Scilla [17]

Both figures are mixtures,

Figure II is a heterogenous mixture

Figure I is a homogenous mixture

5 0
3 years ago
How many moles are in 213 mg of calcium fluoride, CaF2?
lana [24]

Answer:

2.73

Explanation:

2.72815277835894

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Having been heated to 800 K , at some point the tank starts to leak. By the time the leak is repaired, the tank contains only ha
Liula [17]

Answer: The temperature of the gas reduced to 400K.

Explanation:

Stated that ; The pressure remains the same, that is initial and final pressure equals 1atm.

Applying Charles Law

V1/T1 = V2/T2

Initial volume V1 = 1

Final volume V2 = 1/2 (halved)

Initial temperature T1 =800K

Final temperature T2 = ?

(1/800) = (1/2)/T2

T2 = 800/2

T= 400K

Therefore, when the volume is halved, the temperature reduced also to half ( 400K)

3 0
3 years ago
Can someone help?? This is really hard.
Sergeu [11.5K]

Answer:

See Explanation

Explanation:

Let us consider the first two reactions, the initial concentration of CO was held constant and the concentration of Hbn was doubled.

2.68 * 10^-3/1.34 * 10^-3 = 6.24 * 10^-4/3.12 * 10^-4

2^1 = 2^1

The rate of reaction is first order with respect to Hbn

Let us consider the third and fourth reactions. The concentration of Hbn is held constant and that of CO was tripled.

1.5 * 10^-3/5 * 10^-4 = 1.872 * 10^-3/6.24 * 10^-4

3^1 = 3^1

The reaction is also first order with respect to CO

b) The overall order of reaction is 1 + 1=2

c) The rate equation is;

Rate = k [CO] [Hbn]

d) 3.12 * 10^-4 = k [5 * 10^-4] [1.34 * 10^-3]

k = 3.12 * 10^-4  /[5 * 10^-4] [1.34 * 10^-3]

k = 3.12 * 10^-4/6.7 * 10^-7

k = 4.7 * 10^2 mmol-1 L s-1

e) The reaction occurs in one step because;

1) The rate law agrees with the experimental data.

2) The sum of the order of reaction of each specie in the rate law gives the overall order of reaction.

8 0
3 years ago
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