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bixtya [17]
3 years ago
15

What hold elements together to form compounds

Chemistry
2 answers:
Anna35 [415]3 years ago
6 0
Chemical bonds are forces that hold atoms together to make compounds or molecules.
DiKsa [7]3 years ago
6 0

Answer:

Chemical bonds are forces that hold elements together. it can be either covalent or ionic bonds that are these chemical bonds.

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Polyatomic ions
Vitek1552 [10]
I believe the answer is A.
5 0
3 years ago
What amount (moles) of compound is present in 1.00 g of each of the compounds in Exercise 54?
Anika [276]

Answer:

1. Caffeine, C₈H₁₀N₄O₂

Amount = 1.00/194 = 0.00515 moles

2. Ethanol, C₂H₅OH

Amount = 0.0217 moles

3. Dry Ice, CO₂

amount = 0.0227 moles

<em>Note: The question is incomplete. The compound are as follows:</em>

<em> 1. Caffeine, C₈H₁₀N₄O₂;</em>

<em>2. Ethanol, C₂H₅OH;</em>

<em>3. Dry Ice, CO₂</em>

Explanation:

Amount (moles) = mass in grams /molar mass in grams per mole

1. Caffeine, C₈H₁₀N₄O₂

molar mass of caffeine = 194 g/mol

Amount = 1.00 g/194 g/mol = 0.00515 moles

2. Ethanol, C₂H₅OH

molar mass of ethanol = 46 g/mol

Amount = 1.00 g/46 g/mol = 0.0217 moles

3. Dry Ice, CO₂

molar mass of dry ice = 44 g/mol

amount = 1.00 g/44 g/mol = 0.0227 moles

5 0
3 years ago
2Fe + 3Cl2 → 2FeCl3 which of the following options gives the correct reactant ratio?
Mademuasel [1]

<u>Answer:</u> The reactant ratio in the given chemical equation will be: Fe:Cl_2=2:3

<u>Explanation:</u>

Mole ratio is defined as the ratio of the amount of moles of two substances that are participating in a chemical reaction.

In the given chemical equation:

2Fe+3Cl_2\rightarrow 2FeCl_3

The reactants are Fe and Cl_2 and the product is FeCl_3

The mole ratio is basically the stoichiometric ratio of the chemical compounds taking part in a chemical reaction.

The mole ratio of reactants is stoichiometric ratio of Fe and Cl_2, which is:

Fe:Cl_2=2:3

Hence, the reactant ratio in the given chemical equation will be: Fe:Cl_2=2:3

6 0
3 years ago
According to Hund's rule of maximum spin multiplicity, how many singly-occupied orbitals are there in the valence shells of the
leva [86]

Answer:

A) carbon  - 2

B) cobalt  - 3

C) sulfur   - 2

D) fluorine   - 1

E) titanium   - 2

F) germanium  - 2

Explanation:

Hund's rule of maximum multiplicity:-

Firstly, every orbital which is present in the sublevel is singly occupied and then the orbital is doubly occupied.  

(A) Carbon.

The electronic configuration is -  

1s^22s^22p^2

Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, Carbon has 2 singly occupied orbitals.

(B) Cobalt.

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{7}4s^2

Thus, 4s orbital is fully filled and d orbital can singly filled 5 electrons. Thus, 4 electrons will be paired in 2 orbitals and 3 orbitals will be singly filled in cobalt.

(C) Sulfur.

The electronic configuration is -  

1s^22s^22p^63s^23p^4

Thus, 3s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, 2 electrons will be paired in 1 orbital and 2 orbitals will be singly filled in sulfur.

D) fluorine

The electronic configuration is -  

1s^22s^22p^5

Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, 4 electrons will be paired in 2 orbitals and 1 orbital will be singly filled in fluorine.

E) Titanium

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{2}4s^2

Thus, 4s orbital is fully filled and d orbital can singly filled 5 electrons. Thus, 2 orbitals will be singly filled in titanium.

F) Germanium

The electronic configuration is -  

1s^22s^22p^63s^23p^63d^{10}4s^24p^2

Thus, 4s, 3d orbitals are fully filled and p orbital can singly filled 3 electrons. Thus, Germanium has 2 singly occupied orbitals.

4 0
4 years ago
What volume of 0.350 m koh is required to react completely with 24.0 ml of 0.650 m h3po4?
BartSMP [9]

The complete balanced chemical equation for this is:

<span>3KOH  +  H3PO4  -->  K3PO4  +  3H2O</span>

 

First we calculate the number of moles of H3PO4:

moles H3PO4 = 0.650 moles / L * 0.024 L = 0.0156 mol

 

From stoichiometry, 3 moles of KOH is required for every mole of H3PO4, therefore:

moles KOH = 0.0156 mol H3PO4 * (3 moles KOH / 1 mole H3PO4) = 0.0468 mol

 

Calculating for volume given molarity of 0.350 M KOH:

Volume = 0.0468 mol / (0.350 mol / L) = 0.1337 L = 133.7 mL

 

Answer:

<span>133.7 mL KOH</span>

7 0
3 years ago
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