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ololo11 [35]
3 years ago
15

How many significant figures are in the measurement 0.020 km?

Chemistry
1 answer:
OleMash [197]3 years ago
3 0
2 significant figures (if that means #s) .02
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3 years ago
If the density of a 45.0 cm3 block of wood is 0.65 g/ml what is the mass of the wood?
wlad13 [49]

Answer:

\boxed {\tt mass=29.25 \ grams}

Explanation:

The density formula is mass over volume.

d=\frac{m}{v}

Rearrange the formula for the mass, m. Multiply both sides of the formula by v.

d*v=\frac{m}{v}*v

d*v=m

Mass can be found by multiplying the density and volume. The density is 0.65 grams per milliliter and the volume is 45.0 cubic centimeters.

  • A cubic centimeter is equal to a milliliter.
  • Therefore, 45 cubic centimeters also equals 45 milliliters.

d= 0.65 \ g/mL\\v= 45 \ mL

Substitute the values into the formula.

0.65 \ g/mL * 45 \ mL=m

Multiply. Note the milliliters, or mL will cancel out.

0.65 \ g * 45=m

29.25 \ g=m

The mass of the wood is 29.25 grams.

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4 years ago
A researcher is studying the science of attractiveness and asks volunteer test subjects to describe what trait they find most at
julia-pushkina [17]
Answer : Option C) Categoric.

Explanation : According to the question the researcher is studying the science of attractiveness and the test is conducted by the volunteers by showing the images of different people, so here  we can judge that the study is gender based and has to include male or female. Hence, it can be called as categoric variable. 
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answer: A and C

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In a reaction where an OH group is substituted with a Cl, 15.02 g of 3-phenyl-2-butanol (MW=150.2 g/mol) is the starting materia
Brrunno [24]

Answer:

16.81 g of C₁₀H₁₃Cl

Explanation:

When 3-phenyl-2-butanol reacts with HCl it undergoes a substitution reaction to form 2-chloro-3-phenylbutane and water.

C₁₀H₁₄O + HCl ⇄ C₁₀H₁₃Cl + H₂O

The molar mass of 3-phenyl-2-butanol is 150.2 g/mol and the molar mass of 2-chloro-3-phenylbutane is 168.1 g/mol. The molar ratio is 1:1. Then, for 15.02 g of 3-phenyl-2-butanol, the theoretical yield is:

15.02gC_{10}H_{14}O.\frac{168.1gC_{10}H_{13}Cl}{150.2gC_{10}H_{14}O} =16.81gC_{10}H_{13}Cl

8 0
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