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Paul [167]
3 years ago
15

If 190dm of hydrogen gas collected at 20°c and 760mmHg .Calculate it's volume at stp (standard pressure=760mmHg

Chemistry
1 answer:
Andrei [34K]3 years ago
3 0

Answer:

177.1 L

Explanation:

The excersise can be solved, by the Ideal Gases Law.

P . V = n . R . T

In first step we need to determine the moles of gas:

We convert T° from, C° to K → 20°C + 273 = 293K

We convert P from mmHg to atm → 760 mmHg = 1atm

1Dm³ = 1L → 190L

We replace: 190 L . 1 atm = n . 0.082 . 293K

(190L.atm) / 0.082 . 293K = 7.91 moles.

We replace equation at STP conditions (1 atm and 273K)

V = (n . R .T) / P

V = (7.91 mol . 0.082 . 273K) / 1atm = 177.1 L

We can also make a rule of three:

At STP conditions 1 mol of gas occupies 22.4L

Then, 7.91 moles will be contained at (7.91 . 22.4) /1 = 177.1L

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AysviL [449]

According to the research, the correct option is A. The electrons move back and forth is the statement that is true about AC.

<h3>What is AC?</h3>

It is the flow of electric charges through a conductor is called electric current, if said flow of electric current varies in direction from time to time, we speak of alternating current.

Subatomic particles such as protons and electrons have an electrical charge, a physical property that is manifested by the repulsive and attractive forces that exist between them in AC the electrical charge moves back and forth.

Therefore, we can conclude that according to the research, the correct option is A. The electrons move back and forth is the statement that is true about AC.

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3 0
1 year ago
A chemist is looking for an element that reacts similarly to the element lithium (LI). Which would be the best choice?
MatroZZZ [7]
Letter d, because they are both alkali metals (group one)
8 0
3 years ago
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Given the reaction: 3() + () → 3() + 2()
Scilla [17]

Answer:

i think d is the answer for this

3 0
2 years ago
Please Balanced this Equation
Scilla [17]

Answer:

\rm {Cr_2O_7}^{2-} + 6 \; Fe^{2+} + \underbrace{\rm 14\; H^{+}}_{\text{From}\atop \text{Acid}}\to 2\; Cr^{3+} + 6\; Fe^{3+} + 7\; H_2 O.

Explanation:

Consider the oxidation state on each of the element:

Left-hand side:

  • O: -2 (as in most compounds);
  • Cr: \displaystyle \frac{1}{2}(\underbrace{-2}_{\text{ion}} - \underbrace{7\times (-2)}_{\text{Oxygen}}) = +6;
  • Fe: +2 (from the charge of the ion);

Right-hand side:

  • Cr: +3;
  • Fe: +3.

Change in oxidation state:

  • Each Cr atom: decreases by 3 (reduction).
  • Each Fe atom: increases by 1 (oxidation).

Changes in oxidation states shall balance each other in redox reactions. Thus, for each Cr atom on the left-hand side, there need to be three Fe atoms.

Assume that the coefficient of the most complex species \rm Cr_2O_7^{2-} is 1. There will be two Cr atoms and hence six Fe atoms on the left-hand side. Additionally, there are going to be seven O atoms.

Atoms are conserved in chemical reactions. As a result, the right-hand side of this equation will contain

  • two Cr atoms,
  • six Fe atoms, and
  • seven O atoms.

O atoms seldom appear among the products in acidic environments; they rapidly combine with \rm H^{+} ions to produce water \rm H_2O. Seven O atoms will make seven water molecules. That's fourteen H atoms and hence fourteen \rm H^{+} ions on the product side of this equation. Hence the balanced equation. Double check to ensure that the charges on the ions also balance.

\rm {Cr_2O_7}^{2-} + 6 \; Fe^{2+} + \underbrace{\rm 14\; H^{+}}_{\text{From}\atop \text{Acid}}\to 2\; Cr^{3+} + 6\; Fe^{3+} + 7\; H_2 O.

7 0
3 years ago
For the reaction C (s) + H2O (g) --&gt; CO (g) + H2 (g) ΔH = 131.3 kJ/mol and ΔS = 133.6 J/K-mol at 298K. At temperatures greate
TiliK225 [7]

Answer:

The reaction is spontaneous when T> 0.98 Kelvin   OR T> -272.17°C

Explanation:

Step 1: Data given

ΔH = 131.3 kJ/mol = 131300 J/mol

ΔS = 133.6 J/K*mol

T = 298K

Step 2: The balanced equation

C (s) + H2O (g) --> CO (g) + H2 (g)

Step 3: ΔG

For a reaction to be spontaneous, ΔG should be <0

When ΔG > 0 the reaction is spontaneous in the reverse direction.

ΔG = ΔH - TΔS

Since ΔG<0

ΔH - TΔS <0

Step 4: Calculate T where the reaction is spontaneous

ΔH - TΔS <0

131300 J/mol - T*133.6 J/K*mol <0

- T*133.6 J/K*mol < -131300 J/mol

-T <-131300 /133.6

-T< -982.8 Kelvin

T> 982.8 Kelvin   OR T> 709.6°C

The reaction is spontaneous when T> 982.8 Kelvin   OR T> 709.6°C

At 298 K this reaction C (s) + H2O (g) --> CO (g) + H2 (g) is <u>not spontaneous</u>

6 0
3 years ago
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