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aliina [53]
4 years ago
9

As a biologist, you are researching a population of moles. In the course of your research, you identify a nearby population that

occasionally comes into contact with your study population. What best describes the evolutionary process at work?
A. natural selection
B.gene flow
C. mutation
D. genetic drift
E. artificial selection

Chemistry
1 answer:
Natalka [10]4 years ago
4 0

Answer:

The evolutionary process at work is best described by option <em>B. gene flow</em>

Explanation:

<em>Gene flow </em>also known as migration is any movement of individuals, and/or the genetic material they carry, from one population to another. If gene versions are carried to a population where those gene versions previously did not exist, gene flow can be a very important source of genetic variation. In this case, the nearby population <em>migrates </em>to the mole population. The diagram is a good description of the <em>Gene flow </em>process.

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Answer:

if multiple choice e. d. a. if not e.

Explanation:

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3 years ago
You wish to cool a 1.59 kg block of tin initially at 88.0°C to a temperature of 49.0°C by placing it in a container of kerosene
rjkz [21]

Answer:

We need 0.482 L of kerosene

Explanation:

Step 1: Data given

Mass of the block tin = 1.59 kg

Initial temperature tin= 88.0 °C

Final temperature = 49.0 °C

Initial temperature of kerosene = 32.0 °C

Density of kerosene =  820 kg/m³

Specific heat of tin is 218 J/(kg · °C)

Step 2: Calculate mass of kerosene

Heat lost = heat gained

Qtin = -Qkerosene

Q = m*c*ΔT

m(tin) * c(tin) * ΔT(tin) = -m(kerosene) * c(kerosene) * ΔT(kerosene)

⇒ mass of tine = 1.59 kg

⇒ c(tin) = the specific heat of tin = 218 J/ kg*°C

⇒ ΔT(tin) = The change in temperature = T2 - T1 = 49.0 °C - 88.0 °C = -39.0 °C

⇒ mass of kerosene = TO BE DETERMINED

⇒ c(kerosene) = The specific heat of kerosene =  2010 J/kg*°C

⇒ ΔT = 49.0 - 32.0 = 17.0

1.59 kg * 218 J/kg*°C * -39.0 °C = - m(kerosene) * 2010 J/kg*°C *17.0 °C

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m(kerosene) = 0.39562 kg

Step 3: Calculate volume of kerosene

Volume = mass / density

Volume = 0.39562 kg / 820 kg/m³

Volume = 4.82 * 10^-4 m³ = 0.482 L

We need 0.482 L of kerosene

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3 years ago
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Answer:

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Explanation:

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