This problem Is an example of geometrica progression. The formula
for the sum of geometric progression is:
S = a[(r^n)-1] / (r – 1)
Where s is the sum
a is the first term = 1
r is the common ratio = 2 ( because it doubles every year
n is the number of terms = (19) since the first term is when
he was born which he still 0
s = S = 1[(2^19)-1] / (2 – 1)
s = $524,287
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1. is the second choice
2. is the first choice
3. is also the first choice
4. is also the first choice
5. is the last choice
6. is the second choice
7. is the first choice
8. is the last choice
9. is the second choice
10. is the last choice
your welcome brainless answer please.
I'm not sure I understand the question thoroughly but I'll try...
Let's make "x" the amount in the account.
$40 * 4 = $160.
After four months: x - $160
21-5=16
16/-2=-8
x=8
so 3-(-8)=3+8
=11
No order of operations is what you might know as Pemdas ,number of Operations is something iv'e never heard of.