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shepuryov [24]
3 years ago
13

A videographer earns $485 for every wedding he records and $18 for every extra copy of the video his costumers order . How much

money does the videographer earn in a summer during which he records 34 videos and has 87 orders for extra copies? Show your work.
Mathematics
1 answer:
kupik [55]3 years ago
6 0
All you have to do is start by multiplying 485 and 34 (485*34) to find how much he made by just weddings. That should be equal to 16,490. Then you have to multiply 18 by 87 because he charged 18 per copy and there was 87 copies so (18*87). This should now be equal to 1,566. Since you want the total you now should add them which should be 16,490+1,566 and that is equal to 18,056.
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The sum of two numbers is 70 and their difference is 30. Find the two numbers
ikadub [295]

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Our two numbers are 50 and 20

Step-by-step explanation:

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A circle has a circumference of 6. It has an arc of length
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4 0
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businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

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Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
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