Answer:
$944
Step-by-step explanation:
<h3>
Interest=principle*rate*time (in years)</h3><h3>
I=prt</h3>
<em>Principle=800</em>
<em>Rate=0.06 (6%)</em>
<em>Time=3</em>
<em>800*0.06*3= 144</em>
Total
Principle+Interest= Total
800+144=944
To determine the value of the given algebraic expression above, we simply substitute the values of each variable to the variables in the expression and evaluate the expression. We do as follows:
6x(y^2)(z)
when x = 0.5
y = -1
z = 2
6(0.5)((-1)^2)(2)
3(1)(2)
6
The value of the algebraic expression would be 6. An algebraic expression consists of variables which are represented with letters like for this case x, y and z, a coefficient which is indicated by numbers (e.g. 6 ) and exponents like 2 for the expression above. Often times expressions contains a number of terms which consists of those elements.
Answer:
the bottom one doesnt show a correct reflection
Step-by-step explanation:
Compare each place value. It's kind of hard to explain without examples...
If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.
