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natulia [17]
2 years ago
11

3x+2 ≤2 - 3x for x=-2

Mathematics
2 answers:
baherus [9]2 years ago
6 0
(
3
)
(
−
2
)
+
2
≤
2
−
(
3
)
(
−
2
)
−
4
≤ 8
umka21 [38]2 years ago
5 0

Answer:

x=−7

Step-by-step explanation:

Apply the distributive property.

3x−2(3x)−2⋅−2=2(4−x)+33x-2(3x)-2⋅-2=2(4-x)+3

Multiply 33 by −2-2.

3x−6x−2⋅−2=2(4−x)+33x-6x-2⋅-2=2(4-x)+3

Multiply −2-2 by −2-2.

3x−6x+4=2(4−x)+33x-6x+4=2(4-x)+3

Subtract 6x6x from 3x3x.

−3x+4=2(4−x)+3

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Contains the point (-1, 2) and is parallel to<br> x – 2y = -3
ivanzaharov [21]

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange x - 2y = - 3 into this form

Subtract x from both sides

- 2y = - x - 3 ( divide all terms by - 2 )

y = \frac{1}{2} x + \frac{3}{2} ← in slope- intercept form

with m = \frac{1}{2}

• Parallel lines have equal slopes, thus

y = \frac{1}{2} x + c ← is the partial equation

To find c substitute (- 1, 2) into the partial equation

2 = - \frac{1}{2} + c ⇒ c = 2 + \frac{1}{2} = \frac{5}{2}

y = \frac{1}{2} x + \frac{5}{2} ← in slope- intercept form

Multiply through by 2

2y = x + 5 ( subtract 2y from both sides )

0 = x - 2y + 5 ( subtract 5 from both sides )

- 5 = x - 2y, thus

x - 2y = - 5 ← in standard form

4 0
3 years ago
7/7q+21= x /5q^2-45 then x=?​
anzhelika [568]

Answer:

x = 5q - 15

Step-by-step explanation:

\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15

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2 years ago
Plz help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Alexxx [7]

Answer:

1

Step-by-step explanation:

When they say the value of h(x) they're asking what y value is when x=3. Hope this helps!

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Line A is perpendicular to Line B.Line B is perpendicular to Line C.Line C is perpendicular Line D.What can be said about Lines
butalik [34]

We can say that lines A and D are <em>perpendicular</em>.

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2 years ago
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