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Vaselesa [24]
3 years ago
8

A standard galvanic cell is constructed with Sn2+ | Sn and Cu2+ | Cu half cell compartments connected by a salt bridge. Which of

the following statements are correct? (Choose all that apply.)
1. In the external circuit, electrons flow from the Cu2+|Cu compartment to the Sn2+|Sn compartment.
2. The anode compartment is the Sn2+|Sn compartment.
3. The cathode compartment is the Sn2+|Sn compartment.
4. As the cell runs, anions will migrate from the Cu2+|Cu compartment to the Sn2+|Sn compartment.
5. Cu2+ is reduced at the cathode.
Chemistry
1 answer:
Mkey [24]3 years ago
7 0
The answer is letter C
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Answer:

it is possible to remove 99.99% Cu2 by converting it to Cu(s)

Explanation:

So, from the question/problem above we are given the following ionic or REDOX equations of reactions;

Cu2+ + 2e- <--------------------------------------------------------------> Cu (s) Eo= 0.339 V

Sn2+ + 2e- <---------------------------------------------------------------> Sn (s) Eo= -0.141 V

In order to convert 99.99% Cu2 into Cu(s), the equation of reaction given below is needed:

Cu²⁺ + Sn ----------------------------------------------------------------------------> Cu + Sn²⁺.

Therefore, E°[overall] = 0.339 - [-0.141] = 0.48 V.

Therefore, the change in Gibbs' free energy, ΔG° = - nFE°. Where E° = O.48V, n= 2 and F = 96500 C.

Thus, ΔG° = - 92640.

This is less than zero[0]. Therefore,  it is possible to remove 99.99% Cu2 by converting it to Cu(s) because the reaction is a spontaneous reaction.  

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