You would use the equation: Molarity M equals amount of solution over volume of solution. So, 0.758 M equals x L divided by 1.55 L OR 0.758 M = x L / 1.55 L . To solve: 1.55 multiplied by 0.758 equals 1.1479. The answer is 1.1479.

3 0

3 years ago

Which is the most likely to be reduced?

NISA [10]

Answer : The correct option is, $Zn^{2+}$

Explanation :

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. That means, the loss of electrons takes place.

Or we can say that, oxidation reaction occurs when a reactant losses electrons in the reaction.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. That means, the gain of electrons takes place.

Or we can say that, reduction reaction occurs when a reactant gains electrons in the reaction.

According to the electrochemical series, $Zn^{2+}$ most likely to be reduced because

Hence, the ion most likely to be reduced is $Zn^{2+}$ .

3 0

3 years ago

The sodium isotope with 13 neutrons. Express your answer as an isotope

wariber [46]

Answer:

$\large\boxed{\large\boxed{^{24}_{11}Na}}$

Explanation:

The question is asking to write the isotopic symbol of the form $^A_ZX$ for the sodium isotope with 13 neutrons.

In general, the isotopic symbol in the given form shows:

The element's chemical symbol: X

A: mass number of the isotope, written as a superscript to the left of the element's simbol, and

A = number of protons + number of neutrons

Z: atomic number of the isotope, written as a subscript to the left of the elements's symbol,

Z = number of protons

The atomic symbol of sodium is Na.

The atomic number, or number of protons, is the same for every isotope of the element, and you can find it in any periodic table. Tha atomic number of sodium is 11. Thus:

Z = 11

The mass number is the number of protons plus neutrons, hence:

A = 11 + 13 = 24

Now you can write the isotope symbol for the sodium isotope with 13 neutrons:

$^{24}_{11}Na$

6 0

4 years ago