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Fittoniya [83]
4 years ago
8

1. Lani conducted an experiment in which she tested the reactivity of a substance. She placed two

Chemistry
1 answer:
Dima020 [189]4 years ago
4 0

Answer:

the independent variable is the beakers

Explanation:

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How many moles are there in a 3.00M solution when you have 1.78L
frozen [14]
1.78L x (3.00M/1L) = 5.34
3 0
3 years ago
For a cell whose potential is –0.46 v with 3 moles of electrons exchanged, what is ΔG ? ΔG = –nFE°cell
Nimfa-mama [501]
<span>ΔG is 133kJ
</span>
ΔG = –nFE°cell
ΔG =  free energy of the reaction = ?
n = no of moles of electrons exchanged in the reaction = 3
F = Faraday's constant (9.648456 x 10^{4}C/mol)E_{0} =  cell potential = <span>–0.46 v
</span>
⇒ ΔG = –nFE°cell
⇒ ΔG = - (3 mol)(9.648456 x 10^{4} C/mol) (-0.46 J/C) ⇒ ΔG = +133148 J ≈ 133 kJ
4 0
4 years ago
Read 2 more answers
A potential energy diagram is shown. A graph is plotted with Potential Energy in KJ on the y axis and Reaction Pathway on the x
Leya [2.2K]

Answer:

NOT A

Explanation:

3 0
4 years ago
Look at the graph of reaction rate versus substrate concentration for an enzyme. In which region does the reaction rate remain c
OleMash [197]

Answer:

The correct answer is C.

Explanation:

The reaction speed remains constant in region C. This is because the growth rate decreases, tending to zero. Graphically you can see how the slope of the tangent line approaches the horizontal. The slope of the tangent line represents the rate of reaction speed. It is constant because although the concentration continues to increase, the reaction rate does not vary.

Have a nice day!

6 0
4 years ago
A 0.479 g sample of nitrogen, oxygen or neon gas occupies a volume of 265 ml at 157 kpa and 20◦c. what is the molar mass and ide
Anna11 [10]
PV = nRT
P = 157 kPa = 157 × 10³ Pa
V = 265 ml = 0.265 l
T = 20°C = 293 K
m = 0.479 g
PV•M = mRT
M = (mRT)/(PV)
M = 0.479 g × 8.314 kPa.l/(mol.K) × 293 K / (157 kPa × 0.265 l)
M ≈ 28.04579 g/mol.
Hence, the Molar Mass of Dinitrogen or Nitrogen Gas is 28 g.
7 0
3 years ago
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