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pav-90 [236]
3 years ago
8

Fatima is designing an advanced graphics card for a next-generation video game system. She needs to be able to

Chemistry
2 answers:
Bad White [126]3 years ago
4 0

Answer:

semiconducting,tellurium

Explanation:

just completed the assignment

Oksanka [162]3 years ago
3 0

semiconducting, tellurium

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Which two features are used to describe matter?<br> om
andreyandreev [35.5K]

Answer:

Physical properties are used to observe and describe matter. Physical properties can be observed or measured without changing the composition of matter. These are properties such as <em>mass, weight, volume, and density.</em>

6 0
2 years ago
Why is zinc not extracted from ZnO through reduction using CO?​
Jet001 [13]
The standard Gibbs free energy of formation of ZnO from Zn is lower than that of CO2 from CO. Therefore, CO cannot reduce ZnO to Zn. Hence, Zn is not extracted from ZnO through reduction using CO
6 0
1 year ago
Which statement about relative motion is not true?
AURORKA [14]

Explanation:

laws of physics which apply when you are at rest on the earth also apply when you are in any reference frame which is moving at a constant velocity with respect to the earth. For example, you can toss and catch a ball in a moving bus if the motion is in a straight line at constant speed.

7 0
2 years ago
for a neutralization reaction, would you expect the magnitude of q to increase, decrease, or stay the same if the concentration
ikadub [295]

For a neutralization reaction, the value of q(heat of neutralization) is doubled when the concentration of only the acid is doubled.

A neutralization reaction is a reaction in which an acid reacts with a base to yield salt and water. Ionically, a neutralization reaction goes as follows; H^+(aq) + OH^-(aq) ------> H20(l).

The heat of neutralization (Q) of the system depends on the concentration of the solutions. Since Q is dependent on concentration, if the concentration of any of the reactants is doubled, more heat is evolved hence Q is doubled.

Learn more: brainly.com/question/10323185

4 0
2 years ago
Consider the followong balanced reaction. What mads in g of co2 can be formed from 288 mg of o2. Assume that there is excess c3h
Gwar [14]

<u>Answer:</u>

<em>0.264 g of CO_2 can be formed from 288 mg of O_2</em>

<u>Explanation:</u>

The balanced chemical equation is

2 C_3 H_7 OH+9 O_2> 6 CO_2+8 H_2 O

The conversions are  

Mass in mg O_2 is converted to mass in g O_2  

Mass in g O_2 is converted to moles O_2 by dividing with molar mass  

Moles O_2 is converted to moles CO_2  by using the mole ratio of O_2:CO_2 is 9 : 6

Moles CO_2  is converted to mass CO_2 by multiplying with molar mass CO_2

mass in mg O_2  > mass in g O_2 >moles O_2 > moles CO_2 > mass CO_2

288mg O_2 \times \frac{(1g O_2)}{(1000mg O_2 )} \times \frac {(1molO_2)}{(32gO_2 )}\times\frac {(6mol CO_2)}{(9mol O_2 )} \times \frac {(44.0 gCO_2)}{(1mol CO_2 )}

=0.264g (Answer)

7 0
3 years ago
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