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vfiekz [6]
3 years ago
9

You are experimenting to find out if fertilizer makes a plant grow taller. What would be an appropriate control group for this e

xperiment?
Chemistry
1 answer:
leonid [27]3 years ago
3 0

Answer:

If plants are given nitrogen fertilizer, then they will grow taller. ... Factors in an experiment that a scientist PURPOSELY Changes (manipulated) Control Group ... to test various amounts of fertilizer to find out what amount makes plants grow

Explanation:

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<span>a. x and y are atoms of the same element. 

If both atoms contain the same amount of protons, they are always the same element.
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3 years ago
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A cube is 4 cm on each side. What is its volume?<br><br> Answer: 64cm^3
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yeah

Explanation:

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Pollutants may be natural or man-made true or false​
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2 years ago
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How many grams of ammonia must you start with to make 900.00 l of a 0.140 m aqueous solution of nitric acid? assume all the reac
bogdanovich [222]
You need the set of reactions that goes from ammonia to nitric acid.
<span>
1) 4NH3(g)+5O2(g)-->4NO(g)+6H2O(g)

2) 2NO(g)+O2(g)-->2NO2(g)

3) 3NO2(g)+H2O(l)-->2HNO3(aq)+NO(g)

State the ratio of moles of HNO3 to NH3:

4 moles of NH3 produce 4 mole of NO,

4 moles of NO produce 4 moles of NO2

4 moles of NO2 produce 4 * (2 / 3) moles of HNO3 = 8/3 moles of HNO3.

=> (8/3) moles HNO3 : 4 moles NH3

Calculate the number of moles of HNO3 in 900.00 l of 0.140 M solution

M = n / V => n = M * V = 0.140 M * 900.00 liter = 126 moles HNO3

Use proportions:

(</span><span>8/3) moles HNO3 / 4 moles NH3 = 126 moles HNO3 / x

=> x = 126 moles HNO3 * 4 moles NH3 / (8/3 moles HNO3) = 189 moles NH3

Convert moles to grams:

molar mass NH3 = 14 g/mol + 3 * 1g/mol = 17 g/mol

mass in grams = number of moles * molar mass = 189 moles * 17 g/mol = 3213 g

Answer: 3213 g.
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3 0
3 years ago
What is osmotic pressure of a solution that contains 13.7 g of propyl alcohol (C3H7OH) dissolved in enough water to make 500 mL
azamat

Answer:

Π = iMRT ½

Explanation:

111 g

= 0.033 mol

0.033 mol CaCl2

0.09632 kg solvent

= 0.0344 m

13.7 g x 1 mol C3H7OH

60.10 g

0.5 L

(0.0821 L.atm/K.mol) (300.15K

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3 years ago
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