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Lelechka [254]
3 years ago
9

A solution has pH of 9 what is it?​

Chemistry
2 answers:
Vaselesa [24]3 years ago
5 0
Basic. solutions with a pH from over 7 to 14 are bases
romanna [79]3 years ago
3 0
A solution with a pH of 9 is a base. Hope this helps.
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Sugar dissolving in tea is it chemical or physical change?​
coldgirl [10]

Answer:

it is a physical change because when you heat up again a solution of sugar and tea you gonna obtain again sugar

5 0
3 years ago
The diagram shows a certain kind of cell with all of its major parts labeled.
Mashcka [7]

Answer:

I think it's the last one

D. The cell is prokaryotic because it does not have any membrane-bound organelles.

Explanation:

The difference between eukaryotic and prokaryotic cells are that the eukaryotic cells have a nucleus and they have membrane-bound organelles, and prokaryotic cells don't.

Hope this Helps!

5 0
3 years ago
A student dissolved 5.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution
Marianna [84]

Answer:

0.136g

Explanation:

A student dissolved 5.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution and then diluted it with water to give 275. mL of a final solution. How many grams of NO3- ion are there in the final solution?

Co(NO_3)_2(aq)\rightarrow Co^{2+}(aq)+2NO_3^{-}(aq)

Initial mole of Co(NO3)2  =\frac{mass}{molar mass}

=\frac{5.00}{182.94} \\\\=0.02733mol

Mole of Co(NO3)2 in final solution

=\frac{4.00}{100}\times 0.02733\\\\=0.04\times 0.02733\\\\= 0.001093mol

Mole of  NO3- in final solution = 2 x Mole of Co(NO3)2

=2\times 0.001093\\\\=0.002186mol

Mass of  NO3- in final solution is mole x Molar mass of NO3

=0.002186\times62.01\\\\=0.136g

6 0
4 years ago
How many grams of kcl are present in 85.0 ml of 2.10 m kcl? how many grams of kcl are present in 85.0 ml of 2.10 m kcl? 3.02 133
USPshnik [31]
Molarity (M) = moles of the solute (mol) / Volume of the solution (L)

The molarity of the given KCl solution = 2.10 M
Volume of the given KCl solution = 85.0 mL

Hence,
         2.10 M = Moles of KCl / 85.0 x 10⁻³ L
Moles of KCl = 2.10 M x 85.0 x 10⁻³ L
                     = 0.1785 mol

Moles (mol) = Mass (g) / Molar mass (g mol⁻¹)

Molar mass of KCl = 74.56 g mol⁻¹

Hence, 
  0.1785 mol = Mass of KCl / 74.56 g mol⁻¹
Mass of KCl = 0.1785 mol x 74.56 g mol⁻¹
                    = 13.30 g

Hence, mass of given KCl in 85.0 mL is 13.30 g.
3 0
4 years ago
A solution is prepared by combining 5.00 mL of 4.8x10-4 M NaSCN solution, 2.00 mL of 0.21 M Fe(NO3)3 solution and 13.00 mL of 0.
Tcecarenko [31]

Answer:

The analytical concentrations of thiocyanate ions:

[SCN^-]=0.00012 mol/L

The analytical concentrations of ferric ions:

[Fe^{3+}]=0.063 mol/L

Explanation:

Moles (n)=Molarity(M)\times Volume (L)

1) Moles of sodium thiocyanate  = n

Volume of sodium thiocyanate solution = 5.00 mL = 0.005 L

(1 mL = 0.001L)

Molarity of the sodium thiocyanate = 4.8\times 10^{-4} M

n=4.8\times 10^{-4} M\times 0.005 L=2.4\times 10^{-6}mol

1 mole of sodium thiocyanate has 1 mol of thiocyante ions.

So, moles of thioscyanate ions in 2.4\times 10^{-6}mol  of NaSCN.

=1\times 2.4\times 10^{-6}mol=2.4\times 10^{-6}mol

2) Moles of ferric nitrate = n'

Volume of ferric nitrate solution = 2.00 mL = 0.002 L

Molarity of the ferric nitrate = 0.21 M

n'=0.002 M\times 0.21 L=0.00042 mol

1 mole of ferric nitrate has 3 moles of ferric ions.

So number of moles of ferric ions in 0.00042 moles of ferric nitrate is :

3\times 0.00042 mol=0.00126 mol

Volume of nitric acid = 13.00 mL

Total volume by adding all three volumes of solutions = V

V = 5.00 mL + 2.00 mL + 13.00 mL = 20.00 mL = 0.020 L

The analytical concentrations of thiocyanate ions:

[SCN^-]=\frac{2.4\times 10^{-6}mol}{0.020 L}=0.00012 mol/L

The analytical concentrations of ferric ions:

[Fe^{3+}]=\frac{0.00126 mol}{0.020 L}=0.063 mol/L

3 0
3 years ago
Read 2 more answers
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