Answer:
The analytical concentrations of thiocyanate ions:
![[SCN^-]=0.00012 mol/L](https://tex.z-dn.net/?f=%5BSCN%5E-%5D%3D0.00012%20mol%2FL)
The analytical concentrations of ferric ions:
![[Fe^{3+}]=0.063 mol/L](https://tex.z-dn.net/?f=%5BFe%5E%7B3%2B%7D%5D%3D0.063%20mol%2FL)
Explanation:

1) Moles of sodium thiocyanate = n
Volume of sodium thiocyanate solution = 5.00 mL = 0.005 L
(1 mL = 0.001L)
Molarity of the sodium thiocyanate = 

1 mole of sodium thiocyanate has 1 mol of thiocyante ions.
So, moles of thioscyanate ions in
of NaSCN.

2) Moles of ferric nitrate = n'
Volume of ferric nitrate solution = 2.00 mL = 0.002 L
Molarity of the ferric nitrate = 0.21 M

1 mole of ferric nitrate has 3 moles of ferric ions.
So number of moles of ferric ions in 0.00042 moles of ferric nitrate is :

Volume of nitric acid = 13.00 mL
Total volume by adding all three volumes of solutions = V
V = 5.00 mL + 2.00 mL + 13.00 mL = 20.00 mL = 0.020 L
The analytical concentrations of thiocyanate ions:
![[SCN^-]=\frac{2.4\times 10^{-6}mol}{0.020 L}=0.00012 mol/L](https://tex.z-dn.net/?f=%5BSCN%5E-%5D%3D%5Cfrac%7B2.4%5Ctimes%2010%5E%7B-6%7Dmol%7D%7B0.020%20L%7D%3D0.00012%20mol%2FL)
The analytical concentrations of ferric ions:
![[Fe^{3+}]=\frac{0.00126 mol}{0.020 L}=0.063 mol/L](https://tex.z-dn.net/?f=%5BFe%5E%7B3%2B%7D%5D%3D%5Cfrac%7B0.00126%20mol%7D%7B0.020%20L%7D%3D0.063%20mol%2FL)