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Sedaia [141]
2 years ago
11

(need help asap)

Chemistry
1 answer:
stellarik [79]2 years ago
7 0

Explanation:

150 grams is .15 liters

1 mole of gas at STP occupies 22.414 liters

.15 liter of hydrogen represents .15/22.414 =

0.0066922 moles of H2

equation is

Zn + 2HCl → ZnCl2 + H2

1 mole of Zn will make 1 mole of H2

0.0066922 moles of Zn will make 0.0066922 moles of H2

To convert this molar quantity of zinc into grams we simply multiply by the atomic mass of zinc, which is

65.38 g/mol;-

Mass of Zn required = 0.0066922 moles * 65.38 g/mol = 0.4375390381 grams

https://www.quora.com/How-many-grams-of-Zinc-would-you-need-to-react-with-Hydrochloric-acid-to-produce-1-L-of-H2-gas

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If a mixture containing 0.50 moles of N2 and 1.8 moles of H2 is allowed to react according to the equation N2 3H2 2NH3 Group of
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Answer: hydrogen is the limiting reactant.

Explanation:

We have the equation \text{N}_{2}+3\text{H}_{2} \longrightarrow 2\text{NH}_{3}.

This means that for every mole of nitrogen consumed, 3 moles of hydrogen are consumed.

  • Considering the nitrogen, the reaction can occur 0.50 times.
  • Considering the hydrogen, the reaction can occur 1.8/3 = 0.6 times.

Therefore, <u>hydrogen</u> is the limiting reactant.

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6 0
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Read 2 more answers
Be sure to answer all parts. calculate δg ocell for the reaction between cr(s) and cu2+(aq). e ocell = 1.08 j/c. enter your answ
Mademuasel [1]

Answer:

\boxed{-6.29 \times10^{5}\text{ J}}

Explanation:

Step 1. Determine the cell potential

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2×[Cr ⟶ Cr³⁺ + 3e⁻]                  0.744  V

<u>3×[Cu²⁺ + 2e⁻ ⟶ Cu]             </u>   <u>0.3419 V </u>

2Cr + 3Cu²⁺ ⟶ 3Cu  + 2Cr³⁺    1.086  V

Step 2. Calculate ΔG°

\Delta G^{\circ} = -nFE_{\text{cell}}^{^{\circ}} = -6 \times 96 485 \times 1.086 = \text{-629 000 J}\\\\= \boxed{-6.29 \times10^{5}\text{ J}}

6 0
2 years ago
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