All categories

3 years ago

How would decreasing the volume of the reaction vessel affect each of the following equilibria? 2NOBr(g) --> 2NO(g)+Br2(g)

1 answer:

3 0

As per Le Chatelier principle, when a system in equilibrium is disturbed, the reaction will try to compensate the change to restore the equilibrium.

This reaction occurs in gas phase, so the volume is inversely proportional to the pressure.

Then a decrease in volume will cause an increase in pressure, so the system will tend to react in the direction that compensates this increase, this is the system will try to reduce the number of moles of particles to reduce the increase of the pressure.

As you see, there are 3 particles of products (2 of NO and 1 of Br) for every 2 particles of reactant (NOBr).

That means, that the equilibrium will displace to the left, this is the concentration of NOBr will increase while the concentration of NO and Br will decrease.

You might be interested in

What happens when stress builds at faults? Select three options

Stels [109]

Answer:

When Stress builds up at faults, the 3 options that are correct and can happen

- Rock can bend and break;

- Earthquakes develop at Earth's surface

- Forces affect Earth's rocks

Explanation:

This is a Geography question

- Rock can bend and break

When Stress builds up at faults, it leads to a geologic activity that causes a lot of pressure that lead to the movement of the earth's crust. The movement creates such intense pressure on the rocks, that, with time, they twist, bend, and break due to this pressure.

- Earthquakes develop at Earth's surface

As explained earlier, this intense pressure can lead to rocks breaking, as these rocks break inside the earth's crust, the gaps that come into play after the breaking of the rocks causes the remaining rocks to adjust, releasing a lot of force, and subsequently creating earthquakes.

- Forces affect Earth's rocks

As explained earlier, the forces resulting from these intense pressures, affect the earth's rocks. They move them both vertically and horizontally, change their shape and eventually break them.

Hope this Helps!!!

8 0

3 years ago

The leaves of the rhubarb plant contain high concentrations of diprotic oxalic acid (hooccooh) and must be removed before the st

Andrei [34K]

First we have to find Ka1 and Ka2
pKa1 = - log Ka1 so Ka1 = 0.059
pKa2 = - log Ka2 so Ka2 = 6.46 x 10⁻⁵
Looking at the values of equilibrium constants we can see that the first one is really big compared to second one. so, the pH will be affected mainly by the first ionization of the acid.
Oxalic acid is H₂C₂O₄
H₂C₂O₄ ⇄ H⁺ + HC₂O₄⁻
0.0356 M 0 0
0.0356 - x x x
Ka1 = $\frac{[H^+][HC2O4^-]}{[H2C2O4]}$ = x² / 0.0356 - x
x = 0.025 M
pH = - log [H⁺] = - log (0.025) = 1.6

5 0

3 years ago

Fluorite is..

denpristay [2]

Fluorite is harder than gypsum but softer than apatite. Thus, the correct option is B.

<h3>What is the hardness of any element?</h3>

The hardness of any element may be defined as the capability of a material to oppose the process of deformation and remains in actual shape precisely.

According to the table of hardness scales by Mohs, the increasing order of given hardness of given elements is as follows:

Gypsum < Fluorite < Apatite.

Therefore, Fluorite is harder than gypsum but softer than apatite. Thus, the correct option is B.

To learn more about the Hardness of elements, refer to the link:

brainly.com/question/23721736

#SPJ1

5 0

1 year ago

The substance that waves travel though?

Sedaia [141]

C) medium.

The medium of a wave is any substance that carries the wave, or through which the wave travels.Ocean waves are carried by water, sound waves are carried by air, and. the seismic waves of an earthquake are carried by rock and soil.

5 0

3 years ago

A volume of 125 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If

VMariaS [17]

Answer:

41.9 g

Explanation:

We can calculate the heat released by the water and the heat absorbed by the steel rod using the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity

m: mass

ΔT: change in temperature

If we consider the density of water is 1.00 g/mol, the mass of water is 125 g.

According to the law of conservation of energy, the sum of the heat released by the water (Qw) and the heat absorbed by the steel (Qs) is zero.

Qw + Qs = 0

Qw = -Qs

cw × mw × ΔTw = -cs × ms × ΔTs

(4.18 J/g.°C) × 125 g × (21.30°C-22.00°C) = -(0.452J/g.°C) × ms × (21.30°C-2.00°C)

ms = 41.9 g

3 0

3 years ago