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Naya [18.7K]
3 years ago
5

How would decreasing the volume of the reaction vessel affect each of the following equilibria? 2NOBr(g) --> 2NO(g)+Br2(g)

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
3 0
As per Le Chatelier principle, when a system in equilibrium is disturbed, the reaction will try to compensate the change to restore the equilibrium.


This reaction occurs in gas phase, so the volume is inversely proportional to the pressure.


 Then a decrease in volume will cause an increase in pressure, so the system will tend to react in the direction that compensates this increase, this is the system will try to reduce the number of moles of particles to reduce the increase of the pressure.


As you see, there are 3 particles of products (2 of NO and 1 of Br) for every 2 particles of reactant (NOBr).


That means, that the equilibrium will displace to the left, this is the concentration of NOBr will increase while the concentration of NO and Br will decrease.
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Answer:

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We are informed that the reaction is endothermic. An endothermic reaction is one in which energy is absorbed hence ∆H is positive at all temperatures.

Similarly, absorption of energy leads to a decrease in entropy of the reaction system. Hence the change in entropy of the reaction ∆Sreaction is negative at all temperatures.

The change in free energy for the reaction is positive at all temperatures since ∆S reaction is negative then from ∆G= ∆H - T∆S, we see that given the positive value of ∆H, ∆G must always return a positive value at all temperatures.

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Vera_Pavlovna [14]

Please, find the complete question in the picture attached.

Answer:

1. Na₂O

2. AlF₃

3. MgO

4. Ca₃P₂

Explanation:

1. Na⁺ and O²⁻

An ionic compound will be formed when two ions of opposite charge attract each other.

The positive ion is called cation and the negative ion is called anion.

Thus, every ionic compound has a cation and an anion electrostatically bonded.

The ions must combine in a proportion that genders a neutral compound: so you must have as many cations as negative charge has one anion and as many anions as positive charge has one cation.

This is, if the cation has charge +x, there will be x anions, and if the anion has charge -y, there will be y cations.

Simbolically:

Cation:A^{+x}\\ \\ Anion:B^{-y}\\ \\ Compound:A_yB_x

As you see, the subscripts for each element in the chemical formula are obtained by the exchage of the charges of the ions.

Then, for Na⁺ and O²⁻, the subscript for Na will be 2 and the subscript for O will be 1; and the formula of the ionic compound formed by this pair ot ions is:

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2. Al³⁺ and F⁻

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Thus the ionic compound formed by this pair of ions is:

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3. Mg²⁺ and S²⁻

  • The charge 2+ from Mg atom wil become the subscript 2 of S atom, and the charge 2- will become the subscript 2 of Mg atom:

That results in the formula: Mg₂S₂

Except for some special compounds, the chemical formula is simplified, dividing by the least common denominator. In this case, that means that the two 2 subscripts are simplified to 1, and the final chemical formula for the ionic compound formed by this pair of ions is:

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4. Ca²⁺ and P³⁻

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Hence, the ionic compound formed by these two ions is:

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