Half of all the integers are ... all of the positive "counting numbers".
The total number is infinite, so I can't list them here. But if you start at '1 '
and count, you can never name <em>ALL</em> of them, but you can name <em>as many</em>
of them as you want to.
<span> $843.44 is the answer to this problem
</span>
Answer:
This equation is in standard form: ax 1+bx+c=0. Substitute 9 for a, 16 for b, and −112 for c in the quadratic formula 2a−b±b2−4ac.x= 2×9−16± 16^2−4×9(−112)Square 16.x=2×9−16±256−4×9(−112) Multiply −4 times 9.x=2×9−16± 256−36(−112) Multiply −36 times −112.x=2×9−16±256+4032 Add 256 to 4032.x=2×9−16±4288 Take the square root of 4288.x=2×9−16±8+67 Multiply 2 times 9x=18−16±8=67
Step-by-step explanation:
hope this help if not let me know
Answer: 21599373.37618
Step-by-step explanation:
Answer:
x = i√3, -i√3
Step-by-step explanation:
Simply take the root of both sides, then solve.
