11. You’ve done it correctly
12. Let x^2=y
y^2+13y+40=0
(y+8)(y+5)=0
y=8, 5
Since y=x^2
x^2=8 x^2=5
x=+/-√5 x= +/-2√2
13. x^4-x^2-x^2-8=0
x^4-2x^2-8=0
let x^2=y
Y^2-2y-8=0
(y-4)(y+2)=0
y=4, -2
Since y=x^2
X^2=4 X^2=-2
X= +/- 2 This wouldn’t be a real solution
14. It’s pretty much the same process, just substitute y in for x^2. If you’re confused feel free to ask and I can do it, or you can put it through Photomath
15. You’re on the right track so I’m just going to continue from where you left off
x^2(4x+5)-4(x+5)=0
(x^2-4)(4x+5)=0
x= +/- 2 4x=5
x=5/4 or 1 1/4
Hope this helped :)
Answer:
The right answer is Option 2:
Step-by-step explanation:
Point-slope form of equation of a line is given by:
Here m is slope of the line and (x1,y1) is the point from which the line passes.
Given
Slope = m = -3/4
Point = (x1,y1) = (2,-6)
We simply have to put these value into the general form of equation of line in point-slope form
Hence,
The right answer is Option 2:
Answer:
rectangle: 30 in^2
triangle: 12 in^2
composite: 42 in^2
Step-by-step explanation:
area of a rectangle: length times width
area of a triangle: 
composite area: break the area up by shapes you can find the area of, then add it back together
Answer:19.2
Step-by-step explanation:
Elimination
A, they are both linear
linear equations are sometimes given by y=mx+b, equation A, if graphed, produces a hyperbola which is not linear so statement A is false
B they areboth non-linear
equationb is linear so this is false
C equation a is non-linear and equation b is linear
true
C is the answer
