Answer: 0, 4
Step-by-step explanation:
Answer:
Step-by-step explanation:
-10x. All you have to do is subtract -2 from -8 and then put an x there so it’s -10x
Answer:
In 4 years = $1,893.72
In 16 years = $3,810.53
years to contain $2,000 = 4.9371454128
years to contain $2,500 = 8.766692911
Step-by-step explanation:
In 4 years
A = 1,500 (1 + 0.06)^4
= $1,893.72
In 16 years
A = 1,500 (1 + 0.06)^16
= $3, 810.53
to find number of years
t = ln (A/P) / ln (1+r)
when A = 2,000
t = ln(2,000/1,500) / ln(1+0.06)
= 4.9371454128 years
when A = 2,500
t = ln(2,500/1,500) / ln(1+0.06)
= 8.766692911 years
PS: You can also use log in place of ln
Answer:
You need a z-score of at least 1.09 to get accepted.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
![\mu = 20.9, \sigma = 5.6](https://tex.z-dn.net/?f=%5Cmu%20%3D%2020.9%2C%20%5Csigma%20%3D%205.6)
To get accepted into OSU, you need at least a 27. What is the z-score you need to get accepted?
We need to find Z when X = 27. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{27 - 20.9}{5.6}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B27%20-%2020.9%7D%7B5.6%7D)
![Z = 1.09](https://tex.z-dn.net/?f=Z%20%3D%201.09)
You need a z-score of at least 1.09 to get accepted.