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3 years ago

15

Given the two half-cell reactions for copper and iron below

1 answer:

liraira [26]3 years ago

6 0

Answer:

No, i will not use a water pipe consisting of the two metals

Explanation:

Looking at the reduction potential of the both metals, it is clear that an electrochemical cell is set up with iron as the anode and copper as the cathode.

This will make the iron to quickly corrode and eventually destroy the water pipe. It is better to have a set up in which another metal that is higher than iron in the electrochemical series is combined with it.

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Which statement best describes the relationship between observations and conclusions? A. Observations are based on Conclusions B

irga5000 [103]

Answer:

B. Conclusions are based on observations

Explanation:

7 0

3 years ago

vlada-n [284]

Answer:

El cocodrilo se arrastró durante 20.833 segundos.

Explanation:

El enunciado presenta omisiones y errores conceptuales. La forma correcta es la siguiente: <em>"Un cocodrilo se arrastró 25 metros hacia la derecha con una rapidez promedio de 1.2 metros por segundo. ¿Cuántos segundos se arrastró el cocodrilo?"</em>

Consideremos que el cocodrilo tiene un movimiento rectilíneo uniforme, el tiempo requerido para el recorrido se calcula con la siguiente ecuación cinemática:

$t = \frac{x}{v}$ (1)

Donde:

$x$ - Distancia recorrida, en metros.

$v$ - Rapidez del cocodrilo, en metros por segundo.

$t$ - Tiempo, en segundos.

Si $x = 25\,m$ y $v = 1.2\,\frac{m}{s}$ , entonces el tiempo empleado por el cocodrilo es:

$t = \frac{25\,m}{1.2\,\frac{m}{s} }$

$t = 20.833\,s$

El cocodrilo se arrastró durante 20.833 segundos.

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8 0

3 years ago

WHO INVENTED THE LIGHT BOLD, WHO EVER GETS THE ANSWER RIGHT GETS A THANK YOU FROM ME

aivan3 [116]

This is a hard question because BEING BOLD cant be light ya know... but the light bulb.. thomas edison and joseph swan

5 0

3 years ago

Read 2 more answers

How many atoms of hydrogen are in 170 g of hydrogen peroxide (h2o2)?

Ede4ka [16]

I am pretty sure the answer is 1.5*10^25

5 0

3 years ago

ou will prepare 250-mL of this solution using a 30% (m/v) NaOH stock solution. How many mL of the NaOH stock solution will you n

ArbitrLikvidat [17]

Answer:

$\boxed{\text{3.3 mL}}$

Explanation:

You must convert 30 % (m/v) to a molar concentration.

Assume 1 L of solution.

1. Mass of NaOH

$\text{Mass of NaOH} = \text{1000 mL solution } \times \dfrac{\text{30 g NaOH}}{\text{100 mL solution}} = \text{300 g NaOH}$

2. Moles of NaOH

$\text{Moles of NaOH} = \text{300 g NaOH} \times \dfrac{\text{1 mol NaOH}}{\text{40.00 g NaOH}} = \text{7.50 mol NaOH}$

3. Molar concentration of NaOH

$c= \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{7.50 mol}}{\text{1 L}} = \text{7.50 mol/L}$

4. Volume of NaOH

Now that you know the concentration, you can use the dilution formula .

$c_{1}V_{1} = c_{2}V_{2}$

to calculate the volume of stock solution.

Data:

c₁ = 7.50 mol·L⁻¹; V₁ = ?

c₂ = 0.1 mol·L⁻¹; V₂ = 250 mL

Calculations:

(a) Convert millilitres to litres

$V = \text{250 mL} \times \dfrac{ \text{1 L}}{\text{1000 mL}} = \text{0.250 L}$

(b) Calculate the volume of dilute solution

$\begin{array}{rcl}7.50V_{1} & = & 0.1 \times 0.250\\7.50V_{1} &= & 0.0250\\V_{1} & = & \text{0.0033 L}\\& = & \textbf{3.3 mL}\\\end{array}$

$\text{You will need $\boxed{\textbf{3.3 mL}}$ of the stock solution.}$

4 0

3 years ago