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3 years ago

Given the two half-cell reactions for copper and iron below

Chemistry

1 answer:

liraira [26]3 years ago

6 0

Answer:

No, i will not use a water pipe consisting of the two metals

Explanation:

Looking at the reduction potential of the both metals, it is clear that an electrochemical cell is set up with iron as the anode and copper as the cathode.

This will make the iron to quickly corrode and eventually destroy the water pipe. It is better to have a set up in which another metal that is higher than iron in the electrochemical series is combined with it.

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In one to two sentences, explain a similarity and a difference between the particles in liquid water at 100ºC and the particles

mihalych1998 [28]

Answer

The particle theory is used to explain the properties of solids, liquids and gases. The strength of bonds (attractive forces) between particles is different in all three states.

6 0

3 years ago

Read 2 more answers

In general, if a reaction is spontaneous, the reactants possess more free energy than the products.

Inga [223]

In general, if a reaction is spontaneous, the reactants possess more free energy than the products.

<u>TRUE </u>

FALSE

6 0

3 years ago

Which process can separate out the solute from the solvent?

sineoko [7]

Evaporation of the solution

3 0

3 years ago

50 ml of 0.2 M acetic acid is shaken with 10 g activated charcoal. The concentration of acetic acid is reduced to 0.5 times the

Olegator [25]

Answer:

$0.03 g_{acid}/g_{charcoal}$

Explanation:

The amount adsorbed (solute) is the acetic acid, and the adsorbent is the activated charcoal. The mass of the adsorbent is 10 g.

So, we need to calculate the mass of the acetic acid as follows:

$m = n*M = C*V*M$

Where:

n: is the number of moles = C*V

M: is the molecular mass = 60.052 g/mol

C: is the final concentration of the acid = 0.5*0.2 mol/L = 0.10 mol/L

V: is the volume = 50 ml = 0.050 L

$m_{acid} = C*V*M = 0.10 mol/L*0.050 L*60.052 g/mol = 0.30 g$

Now, the amount of solute adsorbed per gram of the adsorbent is:

$\frac{m_{acid}}{m_{charcoal}} = \frac{0.30 g}{10 g} = 0.03 g_{acid}/g_{charcoal}$

Therefore, the amount of solute adsorbed per gram of the adsorbent is 0.03 g/g.

I hope it helps you!

3 0

2 years ago

101. During the making of steel, iron(II) oxide is reduced to metallic iron by treatment with carbon monoxide gas.

Yuki888 [10]

Explanation:

At a certain temperature, iron (II) oxide, FeO, can react with carbon monoxide, CO, to form elemental iron, Fe, and carbon dioxide, CO2. The value of Kp at that temperature is 0.242. What is the pressure of CO2 at equilibrium if a sample of FeO was initially in a container with CO at a pressure of 0.95 atm? The chemical reaction involved in this process is: FeO(s) + CO(g) ⟷ Fe(s) + CO2(

6 0

2 years ago